Answer:
Both air balloon and water balloon data are best modeled by an exponential function.
Step-by-step explanation:
Air balloon
Time (seconds) Volume (cubic centimeters)
0 95
3 69
6 50
9 37
12 27
The relation Volume variation/time is constant for lines, In this case, this value change from point to point, as can be seen next.
(69 - 95)/3 = -8.67
(50 - 69)/3 = -6.33
(37 - 50)/3 = -4.33
(27 - 37)/3 = -3.33
Water balloon
Time (seconds) Volume (cubic centimeters)
0 30
3 15.8
6 7.8
9 4
12 2
(30 - 15.8)/-3 = -4.73
(15.8 - 7.8)/-3 = -2.67
(7.8 - 4)/-3 = -1.27
(4 - 2)/-3 = -0.67
In this case, the relation Volume variation/time also change from point to point.
Then, both air balloon and water balloon data are best modeled by an exponential function.
Answer:
Step-by-step explanation:
Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.
we have to find the length of AB.
Let the side of square i.e AB is x units.
As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°
⇒ CP||MP||AB
In ΔMNP and ΔCND
∠NCD=∠NMP (∵ corresponding angles)
∠NDC=∠NPM (∵ corresponding angles)
By AA similarity rule, ΔMNP~ΔCND
Also, ΔKAP~ΔKPM by similarity rule as above.
Hence, corresponding sides are in proportion
Adding above two, we get
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Answer:nun ya buisness tho
Step-by-step explanation:
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Answer:Find the water height for a weir that is 3 feet long and has flow of 38.4 cubic feet per second. SOLUTION: Therefore, the water height for the weir is 4 feet.
Answer:
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