Given J(1,4) and the midpoint is M(2, 1), find the other endpoint K.

Katrina drinks 0.5 gallons of water per day which expression shows how to find the number of cups of water she drinks in a week

earnstyle [38]

Well we know that 1/2 a gallon (or 0.5 gallons) is equal to 8 cups. So one gallon is 16 cups. (keep this in the back of your mind)

Now to find how many cups she drinks in a day, find out how many gallons she drinks in a week.

So 0.5 (7) = 3.5

Now compute to see how many cups are in 3.5 gallons.

Answer: 56.0001

Understand?

7 0

3 years ago

Read 2 more answers

PLEASE HELP!<br> NO LINKS!<br> I only need help on letter d!!

IRINA_888 [86]

$242.46.............

8 0

3 years ago

Topics in math question

Monica [59]

Answer:24

Step-by-step explanation:

5 0

3 years ago

Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro

lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that $\mu = 0, \sigma = 1$

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{-1.69 - 0}{1}$

$Z = -1.69$

$Z = -1.69$ has a p-value of 0.0455

X = -2.23

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{-2.23 - 0}{1}$

$Z = -2.23$

$Z = -2.23$ has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0

3 years ago

Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w

Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1497, \sigma = 322$

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1520 - 1497}{322}$

$Z = 0.07$

$Z = 0.07$ has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

$P = 0.4721*0.4721 = 0.2229$

22.29% probability that both of them scored above a 1520

8 0

2 years ago