The lengths, in centimeters, of nine earthworms are shown below. 3, 4, 5, 5, 6, 7, 8, 9, 10 What is the median of the data?
mel-nik [20]
The median of the problem is 6 because it is in the middle of the number set of the earthworm sizes.
Answer: 37.69911 in. (Round if necessary)
Steps:
2πr
2·π·6 = 37.69911
Answer:
c ≈ 21
Step-by-step explanation:
By applying cosine rule in the given triangle ABC,
c² = a² + b² - 2abcos(C)
c² = (17)² + (10)² - 2(17)(10)cos(98.8°)
c² = 289 + 100 - 340(-0.1530)
c² = 441.015
c = 21
c ≈ 21
Least Common Multiple (LCM) of 4 and 8 is 8. 4 is 2 x 2, while 8 is 2 x 2 x 2. We take the first two that's shared, second two's that shared, and third two that's note. We have three twos, or 2 x 2 x 2 = 8. So the LCM of 4 and 8 is 8.
Answer:
6 pencils
18 pencils
Step-by-step explanation:
Given that
36 pencils are in 6 packs
Number of packs = 6
Number of pencils = 36
Number of pencils per pack :
Number of pencils / number of packs :
36 / 6 = 6
Hence, 6 pencils per pack
Number of pencils in 3 packs :
Since 6 pencils are in a pack ;
Then, 3 packs = (3 * 6) = 18 pencils
