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kaheart [24]
3 years ago
10

ames bought a movie ticket and wants to pay for some friends. A ticket costs $6, and he has $38. How many friends can he pay for

, and how much money will he have left over?
Mathematics
2 answers:
FromTheMoon [43]3 years ago
6 0

Answer:

$2

Step-by-step explanation:

So, I am gonna go on a gander and say five. You would start by doing this.

5 * 6 = 30

Then you.

30 + 6 = 36

You will have two dollars left over.

Murljashka [212]3 years ago
5 0

Answer:

$2

Step-by-step explanation:

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Zolol [24]

Answer:

Step-by-step explanation:

15x13=?

15+15+1=31

so the answer is 31

8 0
3 years ago
What is 2 (x-3) -(6x-4)
docker41 [41]

Answer:

simplify = - 4 x -2  factored = 2 (-2x - 1)

Step-by-step explanation:

5 0
3 years ago
High School Dropouts
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Answer:

There are more females dropping than males each year and that there are more females than males

7 0
3 years ago
Simplify the trigonometric expression.<br> sin4(α) − cos4(α) + cos2(α)
natulia [17]

Answer:

sin²(α)

Step-by-step explanation:

sin⁴(α) − cos⁴(α) + cos²(α)

sin⁴(α) − cos²(α) (cos²(α) − 1)

sin⁴(α) − cos²(α) (-sin²(α))

sin⁴(α) + sin²(α) cos²(α)

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sin²(α) (1)

sin²(α)

5 0
3 years ago
Use the identity below to complete the tasks:
quester [9]

Answer:

a=[2q^{2}r]

b=[3s^{2}t]

Step-by-step explanation:

we have

8q^{6}r^{3}+27s^{6}t^{3}

we know that

8q^{6}r^{3}=(2^{3})(q^{2})^{3}r^{3}=[2q^{2}r]^{3}

27s^{6}t^{3}=(3^{3})(s^{2})^{3}t^{3}=[3s^{2}t]^{3}

therefore

a=[2q^{2}r]

b=[3s^{2}t]

substitute

a^{3} +b^{3}=(a+b)(a^{2} -ab+b^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([2q^{2}r]^{2} -[2q^{2}r][3s^{2}t]+[3s^{2}t]^{2})

[2q^{2}r]^{3} +[3s^{2}t]^{3}=([2q^{2}r]+[3s^{2}t])([4q^{4}r^{2}] -6[q^{2}r][s^{2}t]+[9s^{4}t^{2}])

7 0
3 years ago
Read 2 more answers
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