Answer:
The simple answer is 15 only
Step-by-step answer:
Given:
mean, mu = 200 m
standard deviation, sigma = 30 m
sample size, N = 5
Maximum deviation for no damage, D = 100 m
Solution:
Z-score for maximum deviation
= (D-mu)/sigma
= (100-200)/30
= -10/3
From normal distribution tables, the probability of right tail with
Z= - 10/3
is 0.9995709, which represents the probability that the parachute will open at 100m or more.
Thus, by the multiplication rule, the probability that all five parachutes will ALL open at 100m or more is the product of the individual probabilities, i.e.
P(all five safe) = 0.9995709^5 = 0.9978565
So there is an approximately 1-0.9978565 = 0.214% probability that at least one of the five parachutes will open below 100m
Answer:
39in.
Step-by-step explanation:
due to scale, cant be 15, as that would be the same length as other side
cant be 91 otherwise it wouldnt be similar if it had the same length as blue triangle which has 39 not 15 as the top side
Answer:
one because it is cilinder
Answer:
Step-by-step explanation:
Im assuming the question was 
if thats not the case then im wrong
