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djyliett [7]
3 years ago
7

(k/3^k)(x-6)^k

Mathematics
1 answer:
enot [183]3 years ago
5 0

\displaystyle\sum_{k\ge0}\frac k{3^k}(x-6)^k

converges by the ratio test for

\displaystyle\lim_{k\to\infty}\left|\frac{\frac{k+1}{3^{k+1}}(x-6)^{k+1}}{\frac k{3^k}(x-6)^k}\right|=\frac{|x-6|}3\lim_{k\to\infty}\frac{k+1}k

The limit is 1, so the series converges as long as

\dfrac{|x-6|}3

which indicates a radius of convergence of 3.

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NeTakaya
Answer:  <span>2,856 ft³ .</span>
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The "base area" is the area of the rectangle:

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Ugo [173]

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