The 5 people can seat in a row in 5! ways
But we need to exclude the ways <span>that ann and bob are seated next to each other which is = 4! * 2!
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So, the number of <span>ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72
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<span>Another solution:
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<span>If ann seated in one of the ends, the number of ways = 3*2
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<span>If ann didn't seat in one of the ends , the number of ways = 2*3
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So, the total number of <span>ways that can <span>ann, bob be seated = 3*2 + 2*3 = 12
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The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72
Answer:
A
Step-by-step explanation:
Discriminant is given by
If it is negative then in quadratic formula the square root part becomes negative which makes the solution complex.
so there cannot be any real solution if the Discriminant is negative or less than 0 ,
The correct option for the given question is
A
Three and Six are the only vertical angles shown above. Hope this helps. :P
The answer is y-3=1/2(x-1)
B/9 is your answer
have a good evening
