I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
Answer:
the one on top= c= -12
the bottom one= f= -15
Step-by-step explanation:
Answer:
there is no question
Step-by-step explanation:
there is no question/angle so i don't know how to help you
Ur answer is 1369 that is ur answer hope it helped and hope u pass
Answer:
6 < x < 8 is decreasing
10 < x < 14 is neither
8 < x < 10 is increasing
4 < x < 6 is increasing
1 < x < 4 is decreasing
Step-by-step explanation:
just see where the line is going up or down
down is decreasing
up is increasing
