7 and 9 so what u do is calculate the graph and done
Answer:
113.04 cm.
Step-by-step explanation:
Step 1: <u>Formula/explain</u>
To find the area of a circle, multiply the radius by itself twice, then multiply the product pi.

Step 2: <u>Solve</u>
According to the word problem, the circle has a diameter of 12. This means it has a radius of 6.
Now, we plug the numbers into formula.

Step 3: <u>Conclude</u>
Therefore, the area of this circle is 113.04 cm.
Ok -13*-8 is 104.
-8*18q is 144q.
Combine an you get:
144q+104
Y = -5x + 9
y = 5x + 7
5x + 7 = -5x + 9
5x + 5x = 9 - 7
10x = 2
x = 2/10 reduces to 1/5
y = 5x + 7
y = 5(1/5) + 7
y = 1 + 7
y = 8
solution is (1/5,8)

can be simplified to by adding the 7 and 10 to get
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.

cannot be simplified any more by combining like terms.
By distributing the 2b into the parentheses, you can simplify the expression:

Here you can just add:

Thus, the only expression that cannot simplify any more using adding like terms is the second,

.