The distance travelled by an object is 50 m.
<h3>What is Distance?</h3>
The distance between two points is the length of the path connecting them.
Here, given equation of distance
S = 1/2 (u + v)t
Where s is the distance traveled by an object (in meters)
initial velocity u (in m/s)
final velocity v (in m/s).
t in seconds.
Now, given values are;
u = 8 m/s ; v = 12 m/s ; t = 5 sec.
S = 1/2 (8 + 12)5
S = 1/2 (20)5
S = 100/2
S = 50 m.
Thus, the distance travelled by an object is 50 m.
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Simplifying
2c + 3 = 3c + -4
Reorder the terms:
3 + 2c = 3c + -4
Reorder the terms:
3 + 2c = -4 + 3c
Solving
3 + 2c = -4 + 3c
Solving for variable 'c'.
Move all terms containing c to the left, all other terms to the right.
Add '-3c' to each side of the equation.
3 + 2c + -3c = -4 + 3c + -3c
Combine like terms: 2c + -3c = -1c
3 + -1c = -4 + 3c + -3c
Combine like terms: 3c + -3c = 0
3 + -1c = -4 + 0
3 + -1c = -4
Add '-3' to each side of the equation.
3 + -3 + -1c = -4 + -3
Combine like terms: 3 + -3 = 0
0 + -1c = -4 + -3
-1c = -4 + -3
Combine like terms: -4 + -3 = -7
-1c = -7
Divide each side by '-1'.
c = 7
Simplifying
c = 7
The value of 7 in that number is 7 because the 7 is in the ones place
We have been given two inequalities 
and 
. We are asked to find the integers that satisfy both inequalities.
Let us solve for our 1st inequality.
Upon combining our both inequalities, we will get:
This means that solution of our inequalities is x values greater than 
and less than 
.
We know that integers between and are: 
.
Therefore, our solution would be 
.
1)
The domain
is every value of x for which f(x) is a real number.
f(x) = 13 / (10-x)
The only x value that would not produce a real number for f(x) is 10, since you
cannot divide a number by zero. Answer is C
2)
F(x)
=(x-6)(x+6)/(x2 - 9)
The vertical asymptotes are x=3 and x=-3. Graph the function on a graphing
calculator to observe the behavior of the function at these points. There is
both a positive and negative vertical asymptote a both x=3 and x=-3. Keep in
mind that the denominator approaches zero at these points, and thus f(x) approaches
either positive or negative infinite, depending on whether the denominator, however small, is a positive or
negative number. Answer is B) 3, -3
3)
F(x) = (x2
+ 4x-7) / (x-7)
Although there is a vertical asymptote as x=7, there is no horizontal asymptote.
This makes sense. As X gets bigger, there is nothing to hold y back from
getting greater and greater. X2 is the dominant term, and it’s only
in the numerator. A) none
4)
(x2 +
8x -2) / (x-2)
This function is very similar in structure to the previous one. Same rules
apply. Dominant term only in the numerator means no horizontal asymptote.
A)None
5)
Our
function approaches 0 as x approaches infinite, and has a vertical asymptote at
x=2 and x=1.
Here’s an easy example: 10 / ((x-2)*(x-1)). At x=2 and x=1, there is both a
positive and negative vertical asymptote. As x approaches infinite, the
numerator is dominated by the denominator, which contains x (actually x2 ),
and thus y approaches zero.
