Y = cos(x)
sqrt(3)/2 = cos(30º)
dy = -sin(x)*dx
dy = -sin(30º)*(pi/180) = (1/2)*(pi/180)
y + dy = cos(x) - sin(x)dx
y + dy = sqrt(3)/2 - (1/2)*(pi/180) = 0.8573
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Hey there! I'm happy to help!
Let's call the hamburgers h and the cheeseburgers c.
h+c=500
c=h-50
Let's plug this value for c into the first equation to solve for h.
h+h-50=500
2h-50=500
Add 50 to both sides.
2h=550
Divide both sides by 2.
h=275
Therefore, 275 hamburgers were sold on Wednesday.
Have a wonderful day! :D
If it takes eight men ten hours, it would take seven men nine hours, six men eight hours, five men seven hours and that brings us to the answer you need. It would take four men six hours.
Maximum. Hope you get it right!!
*see attachment for the figure referred to
Answer/Step-by-step explanation:
1. PN = 29
MN = 13
PM = ?
(Segment addition postulate)
(subtract MN from each side)
(substitute)
2. PN = 34, MN = 19, PM = ?
(sediment addition postulate)
(subtract MN from each side)
(substitute)
3. PM = 19, MN = 23, PN = ?
(Segment addition postulate)
(substitute)
4. MN = 82, PN = 105, PM = ?
(segment addition postulate)
(subtract MN from each side)
(substitute)
5. PM = 100, MN = 100, PN = ?
(Segment addition postulate)
(substitute)
