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Verdich [7]
3 years ago
7

HELP!! Find the solution of this system of equations x - y = 4 - 10x + y = -58

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
4 0

Answer:

Step-by-step explanation:

given: x-y = 4

x=4+y

given: -10x + y = -58

plug in for x

-10(4 + y) + y = -58

-40 - 10y + y = -58

-9y = -18

y = -18 / -9

y = 2

now plug in 2 for y in the first equation

x-2=4

x=6

There is the solution  x=6, y=2  :)

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a salesperson earns a commission of $476 for selling $3400 in merchandise. what is the commission rate?
Artemon [7]

Answer:

Step-by-step explanation:

$476/($3400) = 0.14 = 14%

3 0
3 years ago
The sum of the length of any two sides of a triangle is greater than the length of the third side. And the abc, bc=4 and ac= 8-a
alisha [4.7K]

Answer:

ab<6 units

Step-by-step explanation:

One of the basic property of any triangle is that the sum of the length of any two sides of a triangle is always greater than the length of the third side.

Here we are given a triangle abc, in whicn bc=4

ac= 8-ab

If have to make some conclusion about ab.

As per the property discussed above

ab<ac+bc

ab<8-ab+4

2ab<12

ab<6

Hence the length of ab must be less than 6 units

5 0
3 years ago
What is the function? F(x)=2x^2-3x+1
olasank [31]

Answer:

To satisfy the hypotheses of the Mean Value Theorem a function must be continuous in the closed interval and differentiable in the open interval.

Step-by-step explanation:

As f(x)=2x3−3x+1 is a polynomial, it is continuous and has continuous derivatives of all orders for all real x, so it certainly satisfies the hypotheses of the theorem.

To find the value of c, calculate the derivative of f(x) and state the equality of the Mean Value Theorem:

dfdx=4x−3

f(b)−f(a)b−a=f'(c)

f(x)x=0=1

f(x)x=2=3

Hence:

3−12=4c−3

and c=1.

4 0
3 years ago
Read 2 more answers
X varies directly with<br> y. If x = 60 when<br> y = 75. find x when<br> y = 32.
Alex Ar [27]

Answer:

x=17

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
21. In 4 + In(4x - 15) = In(5x + 19)
Alexxx [7]

Answer:

x=-30;\quad \:I\ne \:0

Step-by-step explanation:

In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)

\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\

\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\

\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:

\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0

3 0
3 years ago
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