<span>You are given the waiting times between a subway departure schedule and the arrival of a passenger that are uniformly distributed between 0 and 6 minutes. You are asked to find the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes.
Le us denote P as the probability that the randomly selected passenger has a waiting time greater than 3.25 minutes.
P = (length of the shaded region) x (height of the shaded region)
P = (6 - 3.25) * (0.167)
P = 2.75 * 0.167
P = 0.40915
P = 0.41</span><span />
9514 1404 393
Answer:
mutually exclusive
Step-by-step explanation:
The formula of interest is ...
P(A or B) = P(A) + P(B) - P(A and B)
Filling in the given values, we have ...
9/10 = 2/5 + 1/2 - P(A and B)
Solving for P(A and B), we get ...
P(A and B) = 2/5 +1/2 -9/10 = 4/10 +5/10 -9/10
P(A and B) = 0
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Events are mutually exclusive when <em>they can never happen at the same time</em>. That is, P(A and B) = 0.
The events A and B are mutually exclusive.
The correct answer is 327,700
The surface area is 216
The Volume is 216
The diagonal is 10.392
