Answer:
For the first 2 for the second 3
Step-by-step explanation:
first would be 1x the second would be -1x
The distance of plane from the starting point is 69.46 km.
Given that the plane first flies 35 km in the direction N30W and then 60 km in the direction N60E.
We have to find the distance of plane from starting point.
We have to use pythagoras theorem in this which says that the square of hypotenuse is equal to sum of squares of the base and perpendicular.

From the figure we can say that P=35 km .and B=60 km
In this we have to find the value of H when P=35 and B=60

=1225+3600
=6946
H=69.46
Hence the distance of plane from starting point is 69.46 km.
Learn more about pythagoras theorem at brainly.com/question/343682
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Answer:
an = 6 (1/4)^(n-1)
Step-by-step explanation:
We're given the first term, a₁ = 6.
The common ratio is a term aₓ divided by the previous term aₓ₋₁.
aₓ = 1/4 aₓ₋₁
aₓ / aₓ₋₁ = 1/4
r = 1/4
Therefore:
an = 6 (1/4)^(n-1)
Your answer is correct, good job!

- Correlation coefficient measures the strength of that relationship.
- Calculating a Pearson correlation coefficient requires the assumption that the relationship between the two variables is linear.
- The relationship between two variables is generally considered strong when their r value is larger than 0.7.
Step-by-step explanation:
<h3>Hope it helps you!!</h3>