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3 years ago

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SOMEONE ANSWER?!!?!?!,!,EMERGENCY Can someone tell me the answer plz plz I’ll give you brainlist and points plz This is my final

test No wrong answers

1 answer:

Vera_Pavlovna [14]3 years ago

6 0

Answer: Should be A)

Explanation:

the size of planets effects the amount of gravitational force each planet has, like jupiter, it has the most gravity.

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Which ones are false? need help please.

kirill [66]

Answer:

A.) False B.)False C.) True D.) False E.) False

Explanation:

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3 years ago

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Which element has exactly ﬁve electrons in the highest principal energy level (the outer shell)?

statuscvo [17]

This question is asking for an element with 5 valence electrons. Just go to the row it is in (excluding transition metals) and count over.
The answer would be c. P

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3 years ago

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The mole fraction of a non-electrolyte (MM 40.0 g/mol) in a saturated aqueous solution is 0.310. What is the molality of the sol

jeka57 [31]

<u>Answer:</u> The molality of non-electrolyte is 24.69 m

<u>Explanation:</u>

We are given:

Mole fraction of saturated aqueous solution = 0.310

This means that 0.310 moles of non-electrolyte is present.

Moles of water (solvent) = 1 - 0.310 = 0.690 moles

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of water = 0.690 moles

Molar mass of water = 18 g/mol

Putting values in above equation, we get:

$0.690mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.690mol\times 18g/mol)=12.42g$

To calculate the molality of solution, we use the equation:

$\text{Molality}=\frac{n_{solute}\times 1000}{W_{solvent}\text{ (in grams)}}$

Where,

$n_{solute}$ = Moles of solute (non-electrolyte) = 0.310 moles

$W_{solvent}$ = Mass of solvent (water) = 12.42 g

Putting values in above equation, we get:

$\text{Molality of non-electrolyte}=\frac{0.310\times 1000}{12.42}\\\\\text{Molality of non-electrolyte}=24.96m$

Hence, the molality of non-electrolyte is 24.69 m

4 0

3 years ago

Plz help me thank you so much for helping

malfutka [58]

The answer to it is A

6 0

3 years ago

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A sample of an unknown gas takes 371 s to diffuse through a porous plug at a given temperature.

blsea [12.9K]

Answer:

125.84 g/mol is the molar mass of the unknown gas.

Explanation:

Let the volume of the gases effusing out be V.

Effusion rate of the unknown gas = $R=\frac{V}{371 s}$

Effusion rate of the nitrogen gas = $r=\frac{V}{175 s}$

Molar mass of unknown gas = m

Mass of nitrogen gas = 28 g/mol

Graham's law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{r}=\sqrt{\frac{28 g/mol}{M}}$

$\frac{\frac{V}{371 s}}{\frac{V}{175s}}=\sqrt{\frac{28 g/mol}{M}}$

$\frac{175 s}{371 s}=\sqrt{\frac{28 g/mol}{M}}$

$M=\frac{28 g/mol\times 371\times 371}{175\times 175}=125.84 g/mol$

125.84 g/mol is the molar mass of the unknown gas.

5 0

3 years ago