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3 years ago

80.0 mL of 0.30 M NaOH and 80.0 mL of 0.30 M HCl are mixed together. What is the approximate pH

Chemistry

1 answer:

Licemer1 [7]3 years ago

6 0

Answer:

Neutral

Explanation:

The number of moles of solute is equal to product of the molar concentration (molarity) and the volume (in liters) of solution.

Since the volumes and the molar concentrations of the NaOH and HCl solutions mixed are equal, each one of them contributes the same number of moles of solute.

Since every mol of NaOH produces one mol of OH⁻ ions and every mol of HCl produces one mol of H⁺ ion, the number of moles of OH ⁻ and H⁺ in solution are equal.

Thus, OH⁻ and H⁺ ions will be neutralized by the reaction:

OH⁻ (aq) + H⁺ (aq) ⇄ H₂O (l)

Which is strongly shifted to the right and has neutral pH.

Hence, you conclude that the approximate pH of the solution is neutral.

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What did Bohr’s model focus on that Rutherford’s model did not?

wlad13 [49]

Answer:

Because Rutherford's model was weak on the position of the electrons, Bohr focused on them. He hypothesized that electrons can move around the nucleus only at fixed distances from the nucleus based on the amount of energy they have. ... However, an electron could never exist in between two energy levels

3 0

3 years ago

An excess of Ba(No3)2 reacts with 250ml of H2SO4 solution to give 0.55g of BaSo4.determine The concentration in moles per litre

Wewaii [24]

Chemical reaction: Ba(NO₃)₂ + H₂SO₄ → BaSO₄ + 2HNO₃.
V(H₂SO₄) = 250 mL ÷ 1000 mL/L = 0,25 L.
m(BaSO₄) = 0,55 g.
n(BaSO₄) = m(BaSO₄) ÷ M(BaSO₄).
n(BaSO₄) = 0,55 g ÷ 233,38 g/mol.
n(BaSO₄) = 0,00235 mol.
From chemical reaction: n(BaSO₄) : n(Ba(NO₃)₂) = 1 : 1.
n(Ba(NO₃)₂) = 0,00235 mol.
c(Ba(NO₃)₂) = n(Ba(NO₃)₂) ÷ V.
c(Ba(NO₃)₂) = 0,00235 mol ÷ 0,25 L.
c(Ba(NO₃)₂) = 0,0095 mol/L.

7 0

3 years ago

What is the empirical formula of a compound that is 24.42 % calcium, 17.07 % nitrogen, and 58.5% oxygen?

REY [17]

Answer:

$CaN_{2} O_{6}$

Explanation:

When calculating an empirical formula from percentages, assume you have a 100g sample. This allows you to convert the percentages directly to grams, because X % of 100g is X grams.

So:

24.42 % = 24.42 g Ca, 17.07% = 17.07g N, 58.5% = 58.5g O

The next step is to divide each mass by their molar mass to convert your grams to moles.

24.42/40.08 = 0.6092 mol

17.07/14.01 = 1.218 mol

58.85/15.99 = 3.680 mol

Then you will divide all of your mol values by the SMALLEST number of moles. This gives you whole numbers that are the mole ratio (subcripts) of the empircal formula.

0.6092 mol/0.6092 mol = 1

1.218 mol/0.6092 mol = 2

3.680 mol/0.6092 mol = 6

So the empirical formula is $CaN_{2} O_{6}$

5 0

2 years ago

The bonds of four salts (MgBr2, NaCl, MgCl2, and NaBr) are evaluated for ionic character based on electronegativity differences

sammy [17]

Answer:

MgBr2 < MgCl2 < NaBr < NaCl

Explanation:

In order to determinate ionic character, we have to subtract the electronegativity from the elements involved. This is known as Pauling rule.

MgBr2 > ΔΕΝ = 1.8

NaCl > ΔΕΝ = 2.3

MgCl2 > ΔΕΝ = 2

NaBr > ΔΕΝ = 2.1

6 0

2 years ago

The first word in the name of an ester is derived from the ________ used in the esterification.

oksian1 [2.3K]

The first word in the name of an ester is derived from the alcohol used in the esterification.

<h3>What is esterification?</h3>

Esterification is a chemical process where an organic acid with the formula is combined with an alcohol molecule having the chemical formula (ROH).

The process of esterification is known to produce an ester molecule and during this phenomenon is released water (H2O).

An example of an esterification reaction occurs when ethanoic acid (i.e., the active ingredient of vinegar) can react with C2H5OH (i.e., ethanol) in order to form the ethyl ethanoate molecule, which is a well-known ester molecule.

In conclusion, the first word in the name of an ester is derived from the Alcohol used in the esterification.

Learn more about esterification here:

brainly.com/question/14028062

#SPJ1

8 0

1 year ago