The temperatue is 0.4 K.
Answer:
Explanation:
As per the kinetic theory of gases, the product of pressure with volume will be equal to the product of concentration and volume. This law is formed by combination of Charle's law and Boyle's law.
Here n = 0.52 mo; P = 131.722 kpa, V = 11.81.
PV = nRT
Here n is the mole concentration, P is the pressure and V is the volume.
(131.722× 10³×11.8)=(0.52×8.314×T)
1.554 = 4.32 T
T = 1.554/4.32=0.4 K
T = 0.4 K.
Thus, the temperatue is 0.4 K.
There are rules to assigning conventional oxidation numbers to some elements. For those unspecified, you can solve them. This is how you solve it.
*S8. Since this is in elemental form, its oxidation number is assigned as 0.
*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.
*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.
*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.
*K₂SO₄. K is assigned with +1.
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.
<em>The S with the highest oxidation number is the one in K₂SO₄.</em>
Answer:
The dynamic viscosity of the liquid is 0.727 kg/m*s
Explanation:
In the equation for that viscosimeter, ν = KR⁴t, <u>the terms K and R are not dependent on the liquid that is being tested</u>, unlike ν and t.
Using that equation and the data given in the problem, we can calculate the product of K and R⁴.
1.19*10⁻³m²/s = (KR⁴)* 1430 s
KR⁴=8,32*10⁻⁷m²/s²
We can now calculate the<em> </em><u><em>kinematic</em></u> viscosity of the unknown liquid.
ν=8,32*10⁻⁷m²/s²*900s
ν=7.49*10⁻⁴m²/s
The relationship between the <em>kinematic</em> viscosity and the <em>dynamic</em> viscosity is given by the equation μ=ν * ρ, where μ is the dynamic viscosity and ρ is the density. Thus:
μ=7.49*10⁻⁴m²/s * 970 kg/m³
μ=0.727 kg/m*s
A homogeneous mixture<span> has the same uniform appearance and composition throughout. Many homogeneous </span>mixtures<span> are commonly referred to as </span>solutions<span>. A </span>heterogeneous mixture <span>consists of visibly </span>different<span> substances or phases. The three phases or states of matter are gas, liquid, and solid.
</span>
The volume of Hydrogen gas : 24 L
<h3>Further explanation</h3>
Given
16 L Ammonia(NH₃)
Required
The volume of Hydrogen gas
Solution
Reaction
N₂ + 3H₂ ⇒ 2NH₃
Avogadro's hypothesis:
In the same T,P and V, the gas contains the same number of molecules
So the ratio of gas volume will be equal to the ratio of gas moles
V₁/n₁=V₂/n₂
From the equation, mol ratio of H₂ : NH₃ = 3 : 2, so volume of H₂ :
= 3/2 x volume of NH₃
= 3/2 x 16 L
= 24 L