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Anuta_ua [19.1K]

3 years ago

12

Copper sulfate is made of one copper (Cu) atom, one sulfur (S) atom, and four oxygen (O) atoms. Write the chemical formula corre

ctly.

1 answer:

Rzqust [24]3 years ago

4 0

The chemical formula for copper sulfate is CuSO4

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Can someone explain me why the molar mass become 90.12 g/mol and when I calculated it's 90 g/mol?

e-lub [12.9K]

Answer:

It could be because of rounding error somewhere in your calculations. Another thing to note is 90 +/- 4 g/mol.

Your calculations don't have to be spot on.

8 0

3 years ago

What is a primary consumer

Ket [755]

Answer:

They eat producers

Explanation:

for example, any herbivore

3 0

3 years ago

Read 2 more answers

If the order of a reaction with the regard to reagent A is 2, when the concentration of A doubles, the rate will

Anarel [89]

Answer:

Rate will double

Explanation:

Since the concentration of A is doubling the rate of reaction will also double, since in this scenario concentration is proportional to rate of reaction. So if the concentration of A were to triple the rate of reaction would also triple.

3 0

2 years ago

How many grams of barium sulfate are produced if 25.34 mL of 0.113 M BaCl2 completely react given the reaction: BaCl2 (aq) + Na2

jeyben [28]

<u>Answer:</u> The amount of barium sulfate produced in the given reaction is 0.667 grams.

<u>Explanation:</u>

To calculate the number of moles from molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of barium chloride = 0.113 M

Volume of barium chloride = 25.34 mL = 0.02534 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$0.113mol/L=\frac{\text{Moles of barium chloride}}{0.02534L}\\\\\text{Moles of barium chloride}=0.00286mol$

For the given chemical reaction:

$BaCl_2(aq.)+Na_2SO_4(aq.)\rightarrow BaSO_4(s)+2NaCl(aq.)$

By Stoichiometry of the reaction:

1 mole of barium chloride is producing 1 mole of barium sulfate.

So, 0.00286 moles of barium chloride will produce = $\frac{1}{1}\times 0.00286mol=0.00286mol$ of barium sulfate.

Now, to calculate the mass of barium sulfate, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of barium sulfate = 233.38 g/mol

Moles of barium sulfate = 0.00286 moles

Putting values in above equation, we get:

$0.00286mol=\frac{\text{Mass of barium sulfate}}{233.38g/mol}\\\\\text{Mass of barium sulfate}=0.667g$

Hence, the amount of barium sulfate produced in the given reaction is 0.667 grams

4 0

3 years ago

4Al(s)+3O2(g)__> 2Al2O3(s)

nasty-shy [4]

What do you want us to work out?

8 0

3 years ago