With arms outstretched,
Moment of inertia is I = 5.0 kg-m².
Rotational speed is ω = (3 rev/s)*(2π rad/rev) = 6π rad/s
The torque required is
T = Iω = (5.0 kg-m²)*(6π rad/s) = 30π
Assume that the same torque drives the rotational motion at a moment of inertia of 2.0 kg-m².
If u = new rotational speed (rad/s), then
T = 2u = 30π
u = 15π rad/s
= (15π rad/s)*(1 rev/2π rad)
= 7.5 rev/s
Answer: 7.5 revolutions per second.
F = ma
200 = 50 * a
4 = a
Therefore acceleration is 4ms^-2
Answer:
4km
Explanation:
displacement is how far something has moved from its starting point
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<h3>
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<h3>
Managerial skills for convenience store</h3>
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- business acumen,
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Thus, the most important managerial skill Freddy needs to have is business acumen because it will improve his business instincts and allow him to guide him team to where they can have the most impact.
Learn more about managerial skills here: brainly.com/question/28072629
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Answer:
Net force, F = 7 N
Explanation:
It is given that,
Initial kinetic energy of the car, 
Final kinetic energy of the car, 
Distance, d = 1 m
We need to find the average net force on the car during this interval. It is given by using the work energy theorem as :
Also, W = F.d d = distance and F = net force
F = 7 Newton
So, the average net force on the car during this interval is 7 newton. Hence, this is the required solution.
