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3 years ago

A Carnot engine has an efficiency of 0.537, and the temperature of its cold reservoir is 379 K.

Physics

1 answer:

katen-ka-za [31]3 years ago

8 0

Answer:

(A) Th = 818.6 K

(B) Qh = 14211.7 J

Explanation:

efficiency (n) = 0.537

temperature of cold reservoir (Tc) = 379 K

heat rejected (Qc) = 6580 J

(A) find the temperature of the hot reservoir (Th)

n = 1 - $\frac{Tc}{Th}$

0.537 = 1 - $\frac{379}{Th}$

$\frac{379}{Th}$ = 1 - 0.537 = 0.463

Th = $\frac{379}{0.463}$

Th = 818.6 K

(B) what amount of heat is put into the engine (Qh) ?

from $\frac{Tc}{Th} = \frac{Qc}{Qh}$

Qh = 6580 ÷ $\frac{379}{818.6}$

Qh = 14211.7 J

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