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zubka84 [21]
3 years ago
8

1. Why is line AC congruent to line CB in the diagram below?

Mathematics
2 answers:
Sonja [21]3 years ago
7 0

Answer:

They are both identical triangles with the same angles and lenght which means they are congruent and so their hypotenuses lines AC and CB are also congruent.

Step-by-step explanation:

Hope this helps

FromTheMoon [43]3 years ago
3 0

Answer:

they are congruent because they are on a perpendicular line

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Step-by-step explanation:

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A survey of students in a school showed 1/2 of the students exercise regularly, 2/5 of the students exercise occasionally and th
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1/10 do not exercise at all.

Step-by-step explanation:

That would be 1 - 1/2 - 2/5

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BRAINLEIST ASAP! PLEASE HELP ME FAST! :)
Arturiano [62]

Answer:

Lines c and b, f and d (option b)

Step-by-step explanation:

To prove whether the lines satisfy the condition of being a transversal to another, let's prove one of the conditions wrong, and thus the answer -

Option 1:

Here lines a and b do not correspond to one another provided they are both transversals, thus don't act as transversals to one another, they simply intersect at a given point.

Option 2:

All conditions are met, lines c and b correspond with one another such that b is a transversal to both c and d. Lines f and d correspond with one another such that f is a transversal to both d and c.

Option 3:

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Option 4:

Lines c and d are both not transversals, thus clearly don't act as transversals to one another.

8 0
3 years ago
Mr. Wells runs a telecommunications company. While going through the company's project records, he found that there were 8 engin
Allisa [31]

There are 12 project managers that are employed by Mr. Wells

<h3>Further explanation</h3>

Solving linear equation mean calculating the unknown variable from the equation.

Let the linear equation : y = mx + c

If we draw the above equation on Cartesian Coordinates , it will be a straight line with :

<em>m → gradient of the line</em>

<em>( 0 , c ) → y - intercept</em>

Gradient of the line could also be calculated from two arbitrary points on line ( x₁ , y₁ ) and ( x₂ , y₂ ) with the formula :

\large {\boxed{m = \frac{y_2 - y_1}{x_2 - x_1}}}

If point ( x₁ , y₁ ) is on the line with gradient m , the equation of the line will be :

\large {\boxed{y - y_1 = m ( x - x_1 )}}

<em>Let us tackle the problem!</em>

\texttt{ }

This problem is about Directly Proportional.

<em>There were 8 engineers under every team leader.</em>

\texttt{1 Team Leader} \rightarrow \texttt{8 engineers}

\texttt{15 Team Leader} \rightarrow 15 \times \texttt{8 engineers} = \boxed{\texttt{120 engineers}}

\texttt{ }

<em>There were 5 project managers for every 50 engineers.</em>

\texttt{50 engineers} \rightarrow \texttt{5 project managers}

\texttt{120 engineers} \rightarrow (120 \div 50) \times \texttt{5 project managers} = \boxed{\texttt{12 project managers}}

\texttt{ }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

7 0
3 years ago
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