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Norma-Jean [14]
3 years ago
6

A 70 Kg man on a 10 kg bike has 1440 J of kinetic energy. How fast is the man moving?

Mathematics
1 answer:
blagie [28]3 years ago
8 0

9514 1404 393

Answer:

  6 m/s

Step-by-step explanation:

The formula for kinetic energy is ...

  KE = (1/2)mv² . . . . m is mass

Filling in the given values, we can solve for v.

  1440 J = (1/2)(70+10 kg)v^2

  (1440 J)/(40 kg) = v^2 = 36 m²/s² . . . . m is meters

  v = √(36) m/s = 6 m/s

The man is moving at  6 meters per second.

_____

In terms of units analysis, the joule (J) is a derived unit equal to ...

  1 J = 1 kg·m²/s²

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