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Ivanshal [37]
3 years ago
15

Question 3 (12 points)

Engineering
1 answer:
Step2247 [10]3 years ago
5 0

so long so long so long so long so long

Explanation:

so long so long so long so long so long so long so long so long so long so long

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How code sould I use to make a robtic arm move
ahrayia [7]
You may have to do your research online for this.
8 0
4 years ago
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Oliver is designing a new children’s slide to increase the speed at which a child can descend. His first design involved steel b
AVprozaik [17]

Answer:

The correct option is;

A) Steel becomes too hot in the Sun and can burn the children

Explanation:

The properties of steel includes;

Low specific heat capacity, high thermal and electrical toughness, high hardness, high tensile strength, high yield strength, appreciable elongation, high fatigue strength, can easily corrode, high malleability and ability to creep

Therefore, due to the low specific heat capacity, which is 0.511 J/(g·°C) and high conductivity of steel which is about 32 W/(m·k), the temperature of the steel can rapidly rise and the hot steel surface can readily conduct the heat, (due to the temperature difference) to other bodies that come in contact

8 0
3 years ago
Where is the specific machine information concerning lubrication/maintenance found?
artcher [175]

The specific machine information concerning lubrication/maintenance found is Preventative Maintenance Manual.

<u>Explanation:</u>

Specific machine information concerning lubrication/maintenance is required for a long life term of the machine as well as for better availability and great profit. The specific machine information concerning lubrication/maintenance found is Preventative Maintenance Manual.

This manual helps the machines to have better maintenance and also prevents the danger that they might occur anytime.

This maintenance helps the equipment process day to day without any issues. Everything is kept under schedule, the past inspections are recorded, and every maintenance scheduled in future are followed under certain time and checks on the service reports.

8 0
4 years ago
A soil element is subjected to a minor principle stress of 50 kPa on a plane rotated 20 ° counterclockwise from vertical. If the
Bad White [126]

Answer:

=>> 167.3 kpa.

=>> 60° from horizontal face.

Explanation:

So, we are given the following data or parameters or information which is going to assist us in solving this kind of question;

=>> "A soil element is subjected to a minor principle stress of 50 kPa on a plane rotated 20 ° counterclockwise from vertical. "

=>>"If the deviator stress is 120 kPa and the shear strength parameters are a friction angle of 30° and a cohesion of 5 kPa."

The orientation of this plane with respect to the major principle stress plane = 50 tan^2 (45 + 30/2) + 10 tan ( 45 + 30/2).

magnitude of the stresses on the failure plane = 167.3 kpa.

The orientation of this plane with respect to the major principle stress plane => x = 60 cos 60° = 30kpa.

y = 60 sin 60° = 30√3 = sheer stress.

the orientation of this plane with respect to the major principle stress plane.

Theta = 45 + 15 = 60°.

5 0
3 years ago
A particle is placed motionless at a point 12m to the right of the origin. Its acceleration as a function of time is a = -30 + 3
kondor19780726 [428]

Answer:

x(t)=-15t^2+5t^3+12

Explanation:

To find the expression for the position x of the particle as a function of time t you need to integrate the expression for acceleration two times. To find the integral constants you are already given the initial conditions for both the position and the velocity which are:

x(t=0)=12\\v(t=0)=0

The first integration gives you the velocity:

v(t)=\int a(t) dt=-30t+15t^2+C_1

You get the constant by using the second initial condition:

C_1=0

To get the expression for the position you need to integrate again:

x(t)=\int v(t)dt=-15t^2+5t^3+C_2

where C_2=12\\ using the first initial condition.

You can now plot the graph. To get the total distance travelled you can integrate the expression for the velocity twice and sum the two integrals (from 0 to 1 and  from 1 to 3):

\int_0^1|v(t)|dt+\int_1^3|v(t)|dt=20 m

3 0
4 years ago
Read 2 more answers
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