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3 years ago

Consider a system whose temperature is 18°C. Express this temperature in R, K, and °F.

Engineering

1 answer:

zvonat [6]3 years ago

7 0

Answer:

In Rankine 524.07°R

In kelvin 291 K

In Fahrenheit 64.4°F

Explanation:

We have given temperature 18°C

We have to convert this into Rankine R

From Celsius to Rankine we know that $T(R)=(T_{C}+273.15)\frac{9}{5}$

We have to convert 18°C

So $T(R)=(18+273.15)\frac{9}{5}=524.07^{\circ}R$

Conversion from Celsius to kelvin

$T(K)=(T_{C}+273)$

We have to convert 18°C

$T(K)=(18+273)=291K$

Conversion of Celsius to Fahrenheit

$T(F)=T_{C}\times \frac{9}{5}+32=64.4^{\circ}F$

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