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2 years ago

Helpppp meeee fassttt pleaseeee

Mathematics

1 answer:

Yuki888 [10]2 years ago

3 0

Answer:

y = -1/3x + 3 2/3

Step-by-step explanation:

step 1. find the slope of the given line

y2-y1/x2-x1 2 - 4/ 3 + 3 = - 1 / 3

take the opposite of that and there is your slope

step 2. plug in the values to the following equation using the given point:

y - y1 = m ( x - x1 ) y - 4 = - 1/3 ( x + 1 )

step 3. solve for y

y-4 = -1/3(x+1)

-1/3(x) and -1/3(1) ----> y-4 = -1/3x-1/3

y-4+4 = -1/3x-1/3+4 ----> y = -1/3x + 3 2/3

<em>hope this helps. if you need more help lmk in the comments. i am in algebra two so you can trust me. Happy holidays</em>

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Sliva [168]

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3 years ago

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 47 units. The base of cylinder B has an

fiasKO [112]

<h3><u>Question:</u></h3>

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

The dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B?

<h3><u>Answer:</u></h3>

Dimensions of cylinder A are multiplied by $\frac{3}{2}$ to produce the corresponding dimensions of cylinder B

<h3><u>Solution:</u></h3>

Cylinders A and B are similar solids.

The base of cylinder A has a circumference of $4 \pi$ units

The base of cylinder B has an area of $9 \pi$ units

Let "x" be the required factor

From given question,

Dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore, we can say,

$\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }$

<h3><u>Cylinder A:</u></h3>

The circumference of base of cylinder (circle ) is given as:

$C = 2 \pi r$

Where "r" is the radius of circle

Given that base of cylinder A has a circumference of $4 \pi$ units

Therefore,

$4 \pi = 2 \pi r\\\\r = 2$

Thus the dimension of cylinder A is radius = 2 units

<h3><u>Cylinder B:</u></h3>

The area of base of cylinder (circle) is given as:

$A = \pi r^2$

Given that, the base of cylinder B has an area of $9 \pi$ units

Therefore,

$\pi r^2 = 9 \pi\\\\r^2 = 9\\\\r = 3$

Thus the dimension of cylinder B is radius = 3 units

$\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }\\\\2 \times x = 3\\\\x = \frac{3}{2}$

Thus dimensions of cylinder A are multiplied by $\frac{3}{2}$ to produce the corresponding dimensions of cylinder B

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Zina [86]

Answer:

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Step-by-step explanation:

Given data;

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