The pythagorean theorem is only used for right triangles? however, you can find the equation with the info given. a circle is written as (x-h)^2+(y-k)^2=r^2. in this scenario, h=-2, k=5, and r=4.
Your final equation would be (x+2)^2+(y-5)^2=16
Answer:
The hikers are 5.9 miles apart.
Step-by-step explanation:
Let O represents the base camp,
Suppose after walking 3.5 miles west, first hiker's position is A, then after going 1.5 miles north from A his final position is B,
Similarly, after walking 2 miles east, second hiker's position is C then going towards 0.5 miles south his final position is D.
By making the diagram of this situation,
Let D' is the point in the line AB,
Such that, AD' = CD
In triangle BD'D,
BD' = AB + AD' = 1.5 + 0.5 = 2 miles,
DD' = AC = AO + OC = 3.5 + 2 = 5.5 miles,
By Pythagoras theorem,


Hence, the hikers are 5.9 miles apart.
Ooooppppppp— homie not gettin nun at home I see
The correct answer is: [D]: " <span>x-int : 1 , y-int: 0.5 " .
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Note:
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The "x-intercept" refers to the point(s) at which the the graph of a function (which is a "line", in this case) cross(es) the "y-axis".
In other words, what is (are) the point(s) of the graph at which "x = 0<span>" ?
</span>
By examining the graph, we see that when " x = 0" ; y is equal to: "1<span>" .
</span>
So; the "x-intercept" is at point: "(0, 1)" ; or, we can simply say that the
"x-intercept" is: "1" .
_________________________________________________________</span> Note:
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The "y-intercept" refers to the point(s) at which the the graph of a function (which is a line, in this case) cross(es) the "x-axis".
In other words, what is (are) the point(s) of the graph at which " y = 0 <span>" ?
</span>
By examining the graph, we see that when " y = 0 " ; x is equal to: "0.5<span>" .
</span>
So; the "x-intercept" is at point: "(0.5, 0)" ; or, we can simply say that the
"y-intercept" is: "0.5 " .<span>
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This would correspond to:<span>
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Answer choice: [D]: </span>" x-int: 1 , y-int: 0.5 " .
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{that is; The "x-intercept" is: "0" ; and the "y-intercept" is: "0.5 ".} .
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