Quiz scores of statistics students were obtained by a teacher and listed below. Construct a frequency distribution beginning wit
1 answer:
Answer:
The frequency distribution is
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
The value for value upper class boundary of the fifth class is
Step-by-step explanation:
From the question we are told that
The lower class limit is 0
The class width is 2
The scores is 8,6,2,4,2,0,2,6,7
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
Generally the upper class boundary of the fifth class is mathematically represented as
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Answer:
The range of z-score is given below as
Answer:
Step-by-step explanation:
y > 3x + 10
y < -3x - 1
<h3> Part A:</h3>You'd graph the given systems of linear inequalities the same way as you graph the linear equations.
To graph y > 3x + 10, plot the y-intercept, (0, 10), then use the slope, m = 3 (rise 3, run 1), to plot other points on the graph. Use a dashed line (because of the ">" symbol).
Follow the same steps for the other linear inequality. Plot the y-intercept, (0, -1), then use the slope, m = -3 (down 3, run 1) to plot other points. Use a dashed line (because of the "<" symbol).
Pick a test point on either side of the boundary line and plug it into the original problem. This will help determine which side of the boundary line is the solution. Plug in a test point that is not on the boundary line.
Use the point of origin, (0, 0) as the test point. Plug in these values into the given systems of linear inequalities to see whether it will provide a true statement.
y > 3x + 10
0 > 3(0) + 10
0 > 0 + 10
0 > 10 (False statement).
y < -3x - 1
0 < -3(0) - 1
0 < 0 - 1
0 < -1 (false statement).
Since the point of origin provided a false statement to the given systems of linear inequalities, you must shade the half-plane region where it doesn't contain the test point.
<h3>Part B: </h3>
You'll do the same process as what I've done for the test point. Plug in the values of (8, 10) into the given systems of linear inequalities. If it provides a false statement, then it means that it is not a solution to the system.
y > 3x + 10
10 > 3(8) + 10
10 > 24 + 10
10 > 34 (False statement).
y < -3x - 1
10 < -3(8) - 1
10 < -24 - 1
10 < -25 (false statement).
Therefore, (8, 10) is not a solution to the system.
