Answer:
The frequency distribution is
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
The value for value upper class boundary of the fifth class is
Step-by-step explanation:
From the question we are told that
The lower class limit is 0
The class width is 2
The scores is 8,6,2,4,2,0,2,6,7
The frequency distribution is
S/N Class limit Frequency
1 0-2 4
2 3 -4 1
3 5-6 2
4 7-8 2
5 9 - 10 0
6 11 - 12 0
Generally the upper class boundary of the fifth class is mathematically represented as
![CB_5 = \frac{10 + 11}{2}](https://tex.z-dn.net/?f=CB_5%20%3D%20%20%5Cfrac%7B10%20%2B%2011%7D%7B2%7D)