Answer:
16
Step-by-step explanation:
the negative outside the parenthesis removes the negative that is with the 19 and it is going to be 19-3 which equal 16
You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.
First, find out what the greatest common factor is between 2, 4, and 5.
<span>This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. </span>
<span>Now we find the list of numbers that are multiples of 20 between 67 and 113. </span>
<span>The solutions are: </span>
<span>80 and 100.</span>
Answer:
3a^2b-5ab^2
Step-by-step explanation:
