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2 years ago

Help! It’s timed and I’m not sure

Mathematics

1 answer:

tensa zangetsu [6.8K]2 years ago

7 0

Answer:

x < 0

Hope this helps!

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Melanie made contributions to a ROTH IRA over the course of working 34 years. Her contributions averaged $3,750 annually.

aleksklad [387]

We assume that we are asked of the monthly contribution made by Melanie to a ROTH IRA. The give data are below:
Period = 34 years * 12 months = 408 months
Total contributions = $3,750
Solving for the monthly contribution, we have the solution below:
Monthly Contribution = Total contribution / period
Monthly contribution = $3750 / 408
Monthly contribution = $9.2

The answer is $9.2 monthly contribution.

8 0

2 years ago

Create a scenario for the following equation: 110x+0

nikklg [1K]

There is no entry fee at an amusement park. It costs $110 per day at the amusement park.

3 0

3 years ago

Can you help me please (get brainliest)

marta [7]

9514 1404 393

Answer:

4/25

Step-by-step explanation:

Put the numbers where the letters are and do the arithmetic.

$\left(2\cdot\dfrac{-1}{2}\cdot\dfrac{2}{5}\right)^2=\left(\dfrac{-2}{5}\right)^2=\dfrac{(-2)^2}{5^2}=\boxed{\dfrac{4}{25}}$

6 0

2 years ago

Please help me with this math question!

barxatty [35]

1) Change radical forms to fractional exponents using the rule:
The n<span>th root of "</span>a number" = "that number" raised to the<span> reciprocal of n.
For example </span> $\sqrt[n]{3} = 3^{ \frac{1}{n} }$ .

The square root of 3 ( $\sqrt{3}$ ) = 3 to the one-half power ( $3^{ \frac{1}{2} }$ ).
The 5th root of 3 ( $\sqrt[5]{3}$ ) = 3 to the one-fifth power ( $3^{ \frac{1}{5} }$ ).

2) Now use the product of powers exponent rule to simplify:
This rule says $a^{m} a^{n} = a^{m+n}
$ . When two expressions with the same base (a, in this example) are multiplied, you can add their exponents while keeping the same base.

You now have $(3^{ \frac{1}{2} })*(3^{ \frac{1}{5} })$ . These two expressions have the same base, 3. That means you can add their exponents:
$(3^{ \frac{1}{2} })(3^{ \frac{1}{5} })\\
= 3^{(\frac{1}{2} + \frac{1}{5}) }\\
= 3^{\frac{7}{10}}$

3) You can leave it in the form $3^{\frac{7}{10}}$ or change it back into a radical $\sqrt[10]{3^7}$

------

Answer: $3^{\frac{7}{10}}$ or $\sqrt[10]{3^7}$

6 0

3 years ago

Write the first 4 terms of the arithmetic sequence With first term 37 and common difference 9

alexandr402 [8]

Answers:

first term = 37

second term = 46

third term = 55

fourth term = 64

==========================================

Explanation:

Start at 37. Add 9 to this term to get the second term. Add 9 to that result to get the next term, and so on.

first term = 37

second term = 37+9 = 46

third term = 46+9 = 55

fourth term = 55+9 = 64

-----------

The nth term formula is

a(n) = 9n+28

It can be found by plugging a = 37 and d = 9 into the general form

a(n) = a + d*(n-1)

4 0

2 years ago

Read 2 more answers