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3 years ago

5

Evaluate 3^2+ (7 - 2). 4 - 6 thirds

1 answer:

natka813 [3]3 years ago

7 0

Answer:

ITS A STRANGE SEQUENCE OF EVENTS MI BOI-REGTOOFUNNY-FUNNYMIKE

Step-by-step explanation:

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Maria is buying new carpet. Her bedroom is in the shape of a square and the length id each side is 12 feet. Write and simplify a

satela [25.4K]

Answer: She needed 144 square feet of carpet.

Step-by-step explanation:

Given : Maria is buying new carpet. Her bedroom is in the shape of a square.

The length of each side is 12 feet.

We know that the area of square = $(side)^2$

So , the area of the bedroom = $(12)^2$ [which is an exponential expression]

Simplify it

The area of the bedroom = $12\times12=144\ \text{ft}^2$

Also, the carpet she needed = Area of the bedroom.

Thus , She needed 144 square feet of carpet.

4 0

3 years ago

Please help with this!!

maw [93]

Answer:

gcf=2

12-2=4(3-1)

hope this is right!

8 0

2 years ago

John works two jobs. He earns $10 an hour babysitting his neighbor's children and $15 an hour mowing lawns in his neighborhood.

Jlenok [28]

Add up all the numbers

7 0

3 years ago

Use the Remainder Theorem to find the remainder for (2x^3-3x^2+6)/(x-1) and state whether or not the binomial is a factor of the

Bezzdna [24]

Answer:

Remainder= 5, and the binomial $(x-1)$ is not a factor of the given polynomial.

Step-by-step explanation:

Given polynomial is $(2x^3-3x^2+6)$ , we have to divide this with a binomial [tex}(x-1)[/tex] using remainder theorem.

Remainder theorem says if $(x-a)$ is a factor then remiander would be $f(a)$

Therefore for $(x-1), \ {we find}\ f(1)}$

$f(1)=(2\times 1^3-3\times1^2+6)\\1^3 =1\\1^2=1\\Substituting \ this \ above\\f(1)= (2-3+6)=5$

Thus the remainder is 5 and since it is not 0 , so the binomial $(x-1)$ is not a factor of the given polynomial.

6 0

3 years ago

Read 2 more answers

Jadyn prepares a bag of candy before a road trip. The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour

kipiarov [429]

Given condition is- The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour Patch Kids.

Let the total number of candies in the bag be = x

Then, Skittles are $\frac{1x}{2}$

Candies left = $x-\frac{x}{2}$ = $\frac{x}{2}$

M&Ms are = $\frac{1x}{8}$

Now remaining candies are= $\frac{3x}{8}$

Now Life savers are = $\frac{9x}{32}$

Now adding all these 3 candies

$\frac{x}{2}+ \frac{x}{8}+\frac{9x}{32}$

= $\frac{29x}{32}$

Now the remaining candies sour patch will be =

$x-\frac{29x}{32} =\frac{3x}{32}$

Hence, sour patch kids are $\frac{3}{32}$

3 0

4 years ago