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Setler [38]
2 years ago
5

What is (-2)(3 4/7)?

Mathematics
1 answer:
Andre45 [30]2 years ago
7 0
-7 and 1/7
hope this helps!!
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rob is asked to graph this system of equations : 6 x +2y = 5 y = 3x =2 how many times will they intersect
ella [17]

Answer:

The lines will not intersect.

Step-by-step explanation:

I took the test and this was the correct answer, there isnt a solution.

4 0
3 years ago
Read 2 more answers
In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it
gavmur [86]

Answer:

a) P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b) P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c)  A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

Step-by-step explanation:

Assuming the following table:

                                                     Purchased Gum      Kept the Money   Total

Students Given 4 Quarters              25                              14                      39

Students Given $1 Bill                       15                               29                    44

Total                                                   40                              43                     83

a. find the probability of randomly selecting a student who spent the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student spent the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{40}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{15}{83}

And if we replace we got:

P(A|B) = \frac{15/83}{44/83} =\frac{15}{44}=0.341

b. find the probability of randomly selecting a student who kept the money, given that the student was given a $1 bill.

For this case let's define the following events

B= "student was given $1 Bill"

A="The student kept the money"

For this case we want this conditional probability:

P(A|B) =\frac{P(A and B)}{P(B)}

We have that P(A)= \frac{43}{83} , P(B)= \frac{44}{83}, P(A and B)= \frac{29}{83}

And if we replace we got:

P(B|A) = \frac{29/83}{44/83} =\frac{29}{44}=0.659

c. what do the preceding results suggest?

For this case the best solution is:

A. A student given a $1 bill is more likely to have kept the money.

Because the probability 0.659 is atmoslt two times greater than 0.341

3 0
3 years ago
Find the area of the circle. Round your answer to the nearest hundredth. 15 in.
Ede4ka [16]

well nearest hundredth is 3

8 0
3 years ago
Read 2 more answers
Finding Side Lengths
zheka24 [161]

Answer:

  • x = 2.5
  • y = 5

Step-by-step explanation:

As the two figure are the image and pre-image of a dilation.

Considering the left sided triangle is original and right sided triangle ( smaller one) is the image.

As one of the sides of the left triangle (original figure) is 4 in. And the corresponding length of the side on the right triangle (image of the figure) is 2 in.

It means the image of the side (2 in) is obtained when the side (4 in) of the original object is dilated by a scale factor of 1/2. In other words, the side of the image (2 in) is obtained multiplying the side (4 in) of original figure by 1/2. i.e. 4/2 = 2 in

Lets determine the missing side of the right side triangle by the same rule.

As the original object has one of the sides is 5 in and the corresponding side of the image has x in. As the original figure is dilated by a scale factor of 1/2. so the missing side of x will be: x = 5/2 = 2.5

So, the value of x will be 2.5

Similarly, the original object has one of the sides with length (y + 1 in). As the As the original figure is dilated by a scale factor of 1/2. As the corresponding length of the side of the image triangle is 3 in.

so

y + 1 = 2(3)         ∵ 3 in (image side) is multiplied by 2

y + 1 = 6

y = 6 - 1

y = 5

So, the value of y = 5

Therefore,

  • x = 2.5
  • y = 5
6 0
3 years ago
Bred has to paint a wall with 8 horizontal stripes. He has enough paint only for 5 blue, 5 red and 5 white stripes. If he can us
Kay [80]

Answer:

336

Step-by-step explanation:

Required Formulas:-

1. Number of ways to select x things out of n things = ⁿCₓ

2. Number of ways to arrange n things when a things and b things are similar = n!/(a!*b!)

Since we have to choose 8 colors and we are having 3 different colors, it is only possible when we select 2 different colors (e.g. 5 red and 3 blue). To find all possible ways we will have to find all unique arrangements of selected color.

Using formula (1), number of ways to select 2 colors out of given 3 colors = ³C₂ = 3

Using formula (2), finding all unique arrangements when 5 stripes are of one color and 3 stripes are of second color = 8!/(3!*5!) = 56

Suppose, we can choose 5 stripes from red color and 3 stripes from blue color or 5 strips from blue color and 3 strips from red color. So there are 2 possibilities of arranging every 2 colors we choose .

∴ Answer=3*56*2 = 336

6 0
3 years ago
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