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3 years ago

rob is asked to graph this system of equations : 6 x +2y = 5 y = 3x =2 how many times will they intersect

Mathematics

2 answers:

Valentin [98]3 years ago

5 0

Answer:

The lines will not intersect

Step-by-step explanation:

AP3X

ella [17]3 years ago

4 0

Answer:

The lines will not intersect.

Step-by-step explanation:

I took the test and this was the correct answer, there isnt a solution.

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Find the precent of change of 15 yards to 18 yards

Delvig [45]

Divide the current with the previous
18/15 = 1.2

move the decimal point to the right two places to get the percentage

120% is your answer

hope this helps

5 0

3 years ago

Read 2 more answers

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

4 0

3 years ago

How much greater is the median number of pairs of shoes in the inventory at the Golf pro Shop than the median number of pairs of

lana66690 [7]

Answer: 20

To get this answer, you find the median of the golf pro shop data (a = 40) and the median of the tennis pro shop data (b = 20). Then you subtract to get a-b = 40-20 = 20. The median of any box plot is the vertical line inside the box plot.

4 0

3 years ago

Does anyone know this answer

4vir4ik [10]

0 is the answer of questions

5 0

3 years ago

The graph of a quadratic equation opens down when the value of is negative.

motikmotik

Answer:

given a quadratic function, y = ax2 + bx + c, when "a" is positive, the parabola opens upward and the vertex is the minimum value. On the other hand, if "a" is negative, the graph opens downward and the vertex is the maximum value

Step-by-step explanation:

6 0

3 years ago