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ludmilkaskok [199]
3 years ago
13

Please help I am struggling so bad

Mathematics
2 answers:
Aleks [24]3 years ago
8 0

9514 1404 393

Answer:

  3.14 units

Step-by-step explanation:

The formula for the length of an arc is ...

  s = rθ

where r is the radius of the circle, and θ is the central angle in radians.

__

The relationship between degrees and radians is ...

  180° = π radians

If we divide this equation by 3, we see ...

  60° = π/3 radians

__

The radius is given as 3 units, so the arc length is ...

  s = (3 units)(π/3) = π units

The arc length is 3.14 units.

kirill [66]3 years ago
3 0
<h2>Answer: </h2>

We know that,

  • <u>Length of arc = 2πrθ/360</u>

Length or arcAB = 2 × 3.14 × 3 × 60/360

= 6.28 × 3/6

= 18.84/6

= 3.14units.

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All of the functions shown below are either exponential growth or decay functions.
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Answer:

Step-by-step explanation:

If an exponential function is in the form of y = a(b)ˣ,

a = Initial quantity

b = Growth factor

x = Duration

Condition for exponential growth → b > 1

Condition for exponential decay → 0 < b < 1

Now we ca apply this condition in the given functions,

1). y=3.2(1+0.45)^{2x}

   Here, (1 + 0.45) = 1.45 > 1

   Therefore, It's an exponential growth.

2). y=(0.85)^{3x}

    Here, (0.85) is between 0 and 1,

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3). y = (1 - 0.03)ˣ + 4

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What is the measure of &lt;1?
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Step-by-step explanation:

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The total number of subsets of {A, B, C} is _____.<br><br> 6<br> 7<br> 8
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Answer:

8

Step-by-step explanation:

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6.6 is the answer to that
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a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5
netineya [11]

9514 1404 393

Answer:

  • 85 ones
  • 70 fives
  • 15 tens
  • 2 fifties

Step-by-step explanation:

Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...

  a +5b +10c +50d = 685 . . . . . total amount of cash

  b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

  a = b+c . . . . . . . . . . . as many ones as fives and tens combined

  d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

__

Substituting for 'a', then for 'b', we have ...

  (b+c) +5b +10c +50d = 685

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Substituting d=2 and subtracting 160 gives ...

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The register contained ...

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