Based on the mass of the circle and the triangle, we can find the mass of the square to be<u> 3.33 grams</u>
<h3>Mass of each side of hanger </h3>
Assuming the mass of the square is x, the equation for the first side is:
= (3 x mass of circle) + (2 x mass of triangle) + (6 x mass of square)
= ( 3 x 2) + ( 2 x 4) + ( 6 × x)
= 6 + 8 + 6x
Mass of other side:
= (2 x mass of circle) + (5 x mass of triangle) + (3 x mass of square)
= ( 2 x 2) + ( 5 x 4) + ( 3 × x)
= 4 + 20 + 3x
<h3>Mass of square </h3>
As both sides are equal, equate both formulas to find x:
6 + 8 + 6x = 4 + 20 + 3x
6x - 3x = 24 - 14
3x = 10
x = 10/3
x = 3.33 grams
In conclusion, each square is 3.33 grams.
Find out more on problems requiring equating at brainly.com/question/20213883.
A quadratic equation is an equation that includes a squared term. For example, 3x + 7 = 28 is not a quadratic equation as it only has x, whereas x^2 + 5x + 6 = 0 is a quadratic equation as it includes x^2. Quadratic equations also usually have two solutions, whereas linear equations (like my first example) only have one.
I hope this helps! Let me know if you would like me to explain anything more :)
Positive integer factors of 100:
1, 2, 4, 5, 10, 20, 25, 50, 100
Now find if they are a multiple of 2 or 3.
2, 4, 10, 20, 50, 100
That is 6 factors.
Answer:
Below.
Step-by-step explanation:
So calculate.
-1/6x+3+1/3x+1=x+4.
Cancel equal terms.
-1/6x+4+1/3x=x+4
Multiply both sides -1/6x+1/3x=x
collect like terms.
-x+2x=6x
move the variable from right to left.
x=6x
collect like terms
x-6x=0
Divide both sides
-5x=0
x=0
Answer:
The required relation is,
= 
Step-by-step explanation:
We know that for a certain amount of dry gas when the pressure is kept constant it's volume V and temperature T is related by the function,
V = cT -----------------------(1) [where "c" is a constant]
So, in that case rate of change of volume(V) with respect to time (t),
=
will be equal to ,
where 
is equal to rate of change of temperature (T) with respect to time (t) and c is the constant stated before.
So, the required relation is,
=
