All categories

3 years ago

What is the result when 3/8x + 2 1/5 is subtracted from 3 1/3x + -4 1/10

Mathematics

1 answer:

Vlad [161]3 years ago

4 0

Answer: The correct answer is the last one shown in the picture

Step-by-step explanation:

It’s the correct answer because when you subtract the two given equations with like terms you will get (- 25/8x + 63/10) —> when you simplify this you get (-3 1/8x + 6 3/10)

You might be interested in

What is the answer to 36 ➗ -12/13

Aleks [24]

Answer:

-39

Step-by-step explanation:

Simplify the following:

36/((-12)/13)

Multiply the numerator of 36/((-12)/13) by the reciprocal of the denominator. 36/((-12)/13) = (36×13)/(-12):

(36×13)/(-12)

The gcd of 36 and -12 is 12, so (36×13)/(-12) = ((12×3) 13)/(12 (-1)) = 12/12×(3×13)/(-1) = (3×13)/(-1):

(3×13)/(-1)

3×13 = 39:

39/(-1)

Multiply numerator and denominator of 39/(-1) by -1:

Answer: -39

8 0

3 years ago

HELP WILL MARK BRAINLIEST

Trava [24]

Look at the attached picture⤴

Hope this will help u...

7 0

3 years ago

Read 2 more answers

For each reaction between a ketone and an amine, draw the curved arrow(s) to show the first step of the mechanism, then draw the

Ray Of Light [21]

Answer:

Step-by-step explanation:

Aromatic amine is generally less nucleophilic than aliphatic amine because of the aromatic delocalisation of the lone pair. Ketones are also less reactive compared to aldehyde and Reaction between aromatic amine and aromatic ketone is possible leading to the formation of Schiff's base in aqeous ethanoic solution.

6 0

3 years ago

How do you do both parts?

AnnZ [28]

Step-by-step explanation:

f(x) = 1 / (5 + x)

Divide top and bottom by 5.

f(x) = ⅕ / (1 + ⅕x)

f(x) = ⅕ / (1 − (-⅕x))

Write as a geometric series.

f(x) = ∑ₙ₌₀°° ⅕ (-⅕x)ⁿ

f(x) = ∑ₙ₌₀°° ⅕ (-1)ⁿ (⅕)ⁿ xⁿ

f(x) = ∑ₙ₌₀°° (-1)ⁿ (⅕)ⁿ⁺¹ xⁿ

Use ratio test:

lim(n→∞)│aₙ₊₁ / aₙ│< 1

lim(n→∞)│[(-1)ⁿ⁺¹ (⅕)ⁿ⁺² xⁿ⁺¹] / [(-1)ⁿ (⅕)ⁿ⁺¹ xⁿ]│< 1

lim(n→∞)│-1 (⅕) x│< 1

│x/5│< 1

│x│< 5

-5 < x < 5

If x = -5, ∑ₙ₌₀°° ⅕ (-1)ⁿ (⅕)ⁿ (-5)ⁿ = ∑ₙ₌₀°° ⅕ (1)ⁿ, which diverges.

If x = 5, ∑ₙ₌₀°° ⅕ (-1)ⁿ (⅕)ⁿ (5)ⁿ = ∑ₙ₌₀°° ⅕ (-1)ⁿ, which diverges.

The interval of convergence is therefore (-5, 5).

4 0

3 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago