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Kay [80]
2 years ago
12

I Need Help!!!!

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
8 0

Answer:

6^27

Step-by-step explanation:

To answer this, we are going to use one of the laws of indices

We have this as;

(a^b)^c = a^(b * c) = a^bc

we are going to apply same here

(6^-3)^-9 = 6^(-3 * -9) = 6^27

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No Links plz<br> help plzz<br> (0000.7x4x6+8to the power of 2)x(16x 8 to the power of 8x5+2)
valentina_108 [34]

Answer:

80.8

Step-by-step explanation: 0.7x4x6=16.8

16.8+8 to the 2nd power= 80.8

6 0
2 years ago
Opposite reciprocal of -2/3? geometry/algebra
Ulleksa [173]
The answer would be -3/2

A reciprocal is the inverse of a number.
When using this in fractions just switch the numerator and denominator. This is done by dividing the fraction by one, but in the case of a negative fraction you would divide by negative 1.
8 0
3 years ago
A lake contains 4 distinct types of fish. Suppose that each fish caught is equally likely to be any one of these types. Let Y de
gregori [183]

a= μ-3.16*σ , b= μ+3.16*σ if each fish caught is equally likely to be any one of these 4 distinct types.

<h3>What is meant by Chebyshev inequality?</h3>

Chebyshev's inequality is a probability theory that ensures that, over a vast range of probability distributions, no more than a particular proportion of values would be present within a selected limits or range as from mean. In other words, only a certain fish caught will be discovered within a given range of the distribution's mean.

The formula for which no more than a particular number of values can exceed is 1/K2; in other words, 1/K2 of a distribution's values can be more than or equal to K standard deviations away from the distribution's mean. Furthermore, it asserts that 1-(1/K2) of a distribution's values must be within, but not include, K standard deviations of the distribution's mean.

How to solve?

from Chebyshev's inequality for Y

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

where

Y =  the number of fish that need be caught to obtain at least one of each type

μ = expected value of Y

σ = standard deviation of Y

P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean

k= parameter

thus for

P(| Y - μ|≤ k*σ ) ≥ 1-1/k²

P{a≤Y≤b} ≥ 0.90 →  1-1/k² = 0.90 → k = 3.16

then

P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90

using one-sided Chebyshev inequality (Cantelli's inequality)

P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)

P{Y≥b} ≥ 0.90  →  1- σ²/(σ²+λ²)=  1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ

then for

P(Y≥ μ+3*σ ) ≥ 0.90

In order to learn more about Chebyshev inequality, visit:

brainly.com/question/24971067

#SPJ4

4 0
1 year ago
A cube has a surface area of 3/2. What's the volume?
Cloud [144]

Answer:

C

Step-by-step explanation:

Assume the surface area = 6x²

6 is the number of faces and x is the length of the cube

so 3/2 = 6x²

Divide by 6

1/4 = x²

Square root both sides

1/2 = x

Volume is : l×w×h

so 1/2 × 1/2 × 1/2 = 1/8

5 0
3 years ago
Read 2 more answers
THIS HOMEWORK IS SO HARD WALLAHI CAN SOMEONE HELP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
Lubov Fominskaja [6]

Answer:

may be 5 I'm not a 100%sure

8 0
3 years ago
Read 2 more answers
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