Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?
1 answer:
<span>6x2 -5x –3 = 0
a = 6 b=-5 and c=-3
x = [-b +-sq root (b² -4ac)] / 2a
x = [--5 +-sq root (25 -4*6*-3)] / 2*6
x = [5 +- sq root (25 +72)] / 12
x = [5 +- sq root (97)] / 12
x1 = [5 + </span><span><span><span>9.8488578018
</span>
</span>
</span>
] / 12
x1 =
<span>
<span>
<span>
14.8488578018
</span>
</span>
</span>
/ 12
x1 =
<span>
<span>
<span>
1.2374048168
</span>
</span>
</span>
x2 = [5 -
<span>
<span>
<span>
9.8488578018
</span>
</span>
</span>
] / 12
x2 =
<span>
<span>
<span>
-4.8488578018
</span>
</span>
</span>
/ 12
x2 =
<span>
<span>
<span>
-0.4040714835
</span>
</span>
</span>
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