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tamaranim1 [39]
3 years ago
15

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

Mathematics
1 answer:
elena55 [62]3 years ago
5 0
<span>6x2 -5x –3 = 0
a = 6 b=-5 and c=-3

x = [-b +-sq root (b² -4ac)] / 2a
x = [--5 +-sq root (25 -4*6*-3)] / 2*6
x = [5 +- sq root (25 +72)] / 12
x = [5 +- sq root (97)] / 12

x1 = [5 + </span><span><span><span>9.8488578018 </span> </span> </span> ] / 12
x1 = <span> <span> <span> 14.8488578018 </span> </span> </span> / 12
x1 = <span> <span> <span> 1.2374048168 </span> </span> </span>

x2 = [5 - <span> <span> <span> 9.8488578018 </span> </span> </span> ] / 12
x2 = <span> <span> <span> -4.8488578018 </span> </span> </span> / 12
x2 = <span> <span> <span> -0.4040714835 </span> </span> </span>


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