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tamaranim1 [39]

4 years ago

15

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x?

1 answer:

elena55 [62]4 years ago

5 0

<span>6x2 -5x –3 = 0
a = 6 b=-5 and c=-3

x = [-b +-sq root (b² -4ac)] / 2a
x = [--5 +-sq root (25 -4*6*-3)] / 2*6
x = [5 +- sq root (25 +72)] / 12
x = [5 +- sq root (97)] / 12

x1 = [5 + </span><span><span><span>9.8488578018 </span> </span> </span> ] / 12
x1 = <span> <span> <span> 14.8488578018 </span> </span> </span> / 12
x1 = <span> <span> <span> 1.2374048168 </span> </span> </span>

x2 = [5 - <span> <span> <span> 9.8488578018 </span> </span> </span> ] / 12
x2 = <span> <span> <span> -4.8488578018 </span> </span> </span> / 12
x2 = <span> <span> <span> -0.4040714835 </span> </span> </span>

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$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

Average $5^{th} \ and \ 6^{th}$ location findings

$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

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3 years ago

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GenaCL600 [577]

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3 years ago

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Fantom [35]

Given:

The function is

$f(x)=-3x^2+2x-7$

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The value of f(-1).

Solution:

We have,

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Putting x=-1, we get

$f(-1)=-3(-1)^2+2(-1)-7$

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3 years ago