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Vikentia [17]
3 years ago
13

758 round to the nearsest hundred

Mathematics
2 answers:
Allisa [31]3 years ago
6 0
If a number has three digits (like 758, 999 or 125) you take a look at the second last digits. If they are higher than 50 you round the first digit up. Otherwise you round it down. Finally you add two zeros.

In case of 758, the last two digits are 58. It is more than 50 so you round 758 to 800.

Hope it helps!
Marta_Voda [28]3 years ago
4 0
Remember, you will round up if the number you are looking at is 5-9 and you will round down if it is 0-4. 758 will be rounded up since we look at the tens place to round to the nearest hundred and it is 5. So, the answer is 800.
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3 years ago
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Answer:

Δ BEC ≅ Δ AED

Step-by-step explanation:

Consider triangles BCA and ADB. Each of them share a common side, AB. Respectively each we should be able to tell that AD is congruent to BC, and DB is congruent to CA, so by SSS the triangles should be congruent.

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So another possibility is triangles BEC, and AED. As you can see, by the Vertical Angles Theorem m∠BEC = m∠ADE, resulting in the congruency of an angle, rather a side. As mentioned before AD is congruent to BC, and perhaps another side is congruent to another in the same triangle. It should be then, by SSA that the triangles are congruent - but that is not an option. SSA does is one of the exceptions, a rule that is not permitted to make the triangles congruent. Therefore, it is highly unlikely that triangles BEC and AED are congruent, but that is what our solution, comparative to the rest.

Δ BEC ≅ Δ AED .... this is our solution

7 0
3 years ago
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3 years ago
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Answer:

1) Combine like terms

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Step-by-step explanation:

1) Combine like terms

2) \sqrt[3]{x} =3

3) cube both sides of the equation

4) 4\sqrt[3]{27} +8\sqrt[3]{27}=36

5) 4(3) + 8(3) = 36

5 0
2 years ago
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