Answer:
diagonal = = 12.8 inches (to the nearest tenth of an inch)
Step-by-step explanation:
As shown in the diagram attached to this solution:
Let the Length of the rectangular board = a
Let the width = b
Let the diagonal = d
where:
a = 10 inches
b = 8 inches
d = ?
Triangle ABC in the diagram is a right-angled triangle, therefore, applying Pythagoras theorem:
(hypotenuse)² = (Adjacent)² + (Opposite)²
d² = 10² + 8²
d² = 100 + 64
d² = 164
∴ d = √(164)
d = 12.806 inches
d = 12.8 inches (to the nearest tenth of an inch)
<em>N:B Rounding off to the nearest tenth of an inch is the same as rounding off to 1 decimal place.</em>
Answer:
yes, you got it correct
Step-by-step explanation:
Answer:
what is the question
Step-by-step explanation:
Questions for answers
F(x) = x^5 - x^3 + x
f'(x) = 5x^4 - 3x^2 + 1
f(3) = (3)^5 - (3)^3 + 3 = 243 - 27 + 3 = 219
f'(3) = 5(3)^4 - 3(3)^2 + 1 = 5(81) - 3(9) + 1 = 405 - 27 + 1 = 379
Let the required equation of the tangent line be
y = mx + c; where y = 219, m = 379, x = 3
219 = 379(3) + c = 1,137
c = 219 - 1,137 = -918
Therefore, required equation is
y = 379x - 918
The first step to determining the answer to this item is to calculate for the effective interest using the equation,
ieff = (1 + i/m)^m - 1
where ieff is the effective interest, i is the given interest and m is the number of compounding period.
Part A: m in this item is equal to 12.
Substituting,
ieff = (1 + 0.10/12)^12 - 1 = 0.1047
The amount of money after n years is calculated through the equation,
An = A(1 + ieff)^n
If An/A = 2 then,
2 = (1 + 0.1047)^n
The value of n is 6.96 years
Part B: For the continuously compounding,
An = Ae^(rt)
An/A = 2 = e^(0.10t)
The value of t is equal to 6.93 years.
Hence, the answers:
<em>Part A: 6.96 years</em>
<em>Part B: 6.93 years</em>
