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yanalaym [24]
3 years ago
7

Can somebody help me on this thank you it will mean a lot

Mathematics
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

your will be A

Step-by-step explanation:

hoped i helped and can i get brainiest pls

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What is 3p + 6p with simplifying?
velikii [3]


3p + 6p = 9p.


It is the same as adding the numbers when you have the same terms (letters).

In this case, it is P.


Hope I helped:)


~FabSafxo

4 0
3 years ago
Read 2 more answers
Take the number you are given, double the difference between your number and 5, add four, divide by 2. If the first number is 12
ANTONII [103]

Answer:

3

Step-by-step explanation:

Here's the rundown of values:

12=9

9=6

6=3

3rd value=3

*The values are created through going through the numerical process.

7 0
3 years ago
a pharmacist has 10 and 90 iodine solutions on hand. how many liters of each iodine solution will be required to produce 8 liter
Westkost [7]
1 litre of 10% solution contains 100mL of iodine
1 litre of 90% solution contains 900mL of iodine
Mixing them will produce 2 litres of solution containing 1000mL of iodine which is 50% iodine.
To produce 8 litres of 50% iodine they can mix 4 litres of 10% and 4 litres of 90%
6 0
2 years ago
Addi places the letters from the word DECEMBER into a bag, a letter will be randomly selected and not replaced. Thnen another le
yuradex [85]

Answer:

Step-by-step explanation:

for c it would be 1\8

for E it would be 3\8

4 0
3 years ago
Read 2 more answers
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

7 0
3 years ago
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