Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
I believe the answer is A
Answer:
second difference
Step-by-step explanation:
The differences of the y-values will differ by a common amount.
<u>Example</u>:
y = x^2 for x = 2, 4, 6, 8
y-values are 4, 16, 36, 64
differences of these are 12, 20, 28
differences of these differences are 8 and 8, a common value.
3+(-5)x=19
Subtract 3 from both sides of the equation.
-5x= 16
Divide by -5 on both sides
X= -3.2
25% is your answer........