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finlep [7]
3 years ago
13

Bryce is testing whether school is more enjoyable when students are making high grades. He asked 100 students if they enjoyed sc

hool and whether their GPA was
above or below 3.0. He found that 33 of the 40 students with a GPA above 3.0 reported that they enjoyed school, and 5 of the 60 students with a GPA below 3.0
reported that they enjoyed school. What is the probability that a student with a GPA below 3.0 does not enjoy school?
Mathematics
1 answer:
GrogVix [38]3 years ago
8 0
Hiiiiiiii The answer would be D
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If ||| m, solve for x and y.
rosijanka [135]

Answer:

x = 11, y = 3

Step-by-step explanation:

(13x - 19) and (9x + 25) are corresponding angles and congruent, thus

13x - 19 = 9x + 25 ( subtract 9x from both sides )

4x - 19 = 25 ( add 19 to both sides )

4x = 44 ( divide both sides by 4 )

x = 11

Then

13x - 19 = 13(11) - 19 = 143 - 19 = 124

(17y + 5) and 124 are alternate angles and are supplementary, thus

17y + 5 + 124 = 180, that is

17y + 129 = 180 ( subtract 129 from both sides )

17y = 51 ( divide both sides by 17 )

y = 3

4 0
3 years ago
Read 2 more answers
What is the common ratio for the geometric sequence?<br> 32, 8, 2, 1/2,....
Brums [2.3K]

Answer:

1/4 is the common ratio for the geometric sequence

5 0
3 years ago
Assume that the radius r of a sphere is expanding at a rate of 40 cm/min. The volume of a sphere is V = 4 3 πr3 and its surface
Scrat [10]

Answer:

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

Step-by-step explanation:

The area of a sphere is given by the following formula:

A = 4\pi r^{2}

In which A is the area, measured in cm², and r is the radius, measured in cm.

Assume that the radius r of a sphere is expanding at a rate of 40 cm/min.

This means that \frac{dr}{dt} = 40

Determine the rate of change in surface area when r = 20 cm.

This is \frac{dA}{dt} when r = 20. So

A = 4\pi r^{2}

Applying implicit differentiation.

We have two variables, A and r, so:

\frac{dA}{dt} = 8r\pi \frac{dr}{dt}

\frac{dA}{dt} = 8*20\pi*40

\frac{dA}{dt} = 20106.19

The rate of change in surface area when r = 20 cm is 20,106.19 cm²/min.

6 0
3 years ago
Can anyone help me with this equation?
beks73 [17]

Answer:

false

Step-by-step explanation:

5+2=15÷(3+2)

5+2=15÷5

7=15÷5

7=3

false because they are different

4 0
3 years ago
Read 2 more answers
6z-4-z+10=-9 plz help and hurry
Anna35 [415]
6z -4 - z + 10 = -9
Combine like terms
5z + 6 = -9
Subtract both sides by 6
5z = -15
Divide both sides by 5
z = -3
Have an awesome day! :)
7 0
3 years ago
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