Y=(-2/3x)+2
You don’t have to include the parentheses. I just placed them there so you know that it’s -2 over 3x plus 2
Answer:
set both of them equal to each other:
8x - 8° = 5x + 25°
subtract 5x by both sides of the equations and it becomes:
3x-8° = 25°
now add 8° both sides:
3x = 33°
divide three by both sides:
x = 11°
now thats done to find B:
plug your x value in the B equation:
5x + 25°
5(11) +25°
55 +25°
not sure if you can add here sorry :(. I hope this helped so far :)
2. it can't have three because one of them is a right triangle do D doesn't add up. It can't have 0 because an obtuse angle plus a right angle would go over 180 degrees. So, the most it can have is 2 acute for example 90(right angle) 30(acute) and 60 (acute) is a possible answer. Also, a right angle can only have two acute angles since an obtuse angle would put it over 180 which was already stated
I don't get you but if you transform the equation to it's standard form, it will be
3x+4y=4
First, Multiply each term by 4:
y(4)=-3x/4(4)+1(4)
4y=-12x/4+4
4y=-3x+4
Now add 3x to both sides of the equation:
4y+3x=-3x+3x+4
3x+4y=0+4
3x+4y=4
Answer:
TC (A) = 40x , TC (B) = 500 + 20x
Step-by-step explanation:
Let the number of students be = x
Hall A Total Cost
Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x
Hall B Total Cost
Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x
