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MArishka [77]
3 years ago
7

1. The value of y varies directly with x. If y = 30 when x =1/5

Mathematics
1 answer:
algol [13]3 years ago
6 0

Answer:

4. b) 30

5. c) y=2/3x+9

6. y=2x-5

Step-by-step explanation:

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Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and
jenyasd209 [6]

Equation of a line is x+3y =-3.

<h3>What is a perpendicular bisector of the line segment?</h3>

A perpendicular bisector is a line that cuts a line segment connecting two points exactly in half at a 90 degree angle. To find the perpendicular bisector of two points, all you need to do is find their midpoint and negative reciprocal, and plug these answers into the equation for a line in slope-intercept form.

Given that,

Endpoints of the line segment are (x_{1},y_{1}) = (4, 1) and (x_{2},y_{2}) = (2, -5).

First find the midpoints of the given line segment.

M = \left(\frac{x_{1}+x_{2}  }{2},\frac{y_{1}+y_{2}  }{2}\Right)

    =  \left(\frac{4+2  }{2},\frac{1-5  }{2}\Right)

M   =  (3,-2)

Now, Find the slope of the line :

It is perpendicular to the line with (4,1) and (2,-5)

Slope between (x_{1},y_{1}) and (x_{2},y_{2}) = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

so,

the slope between (4,1) and (2,-5)  =  \frac{-5-1  }{2-4 }

                                                         = 3

perpendicular lines have slopes the multiply to get -1

3 times m=-1

m= \frac{-1}{3}

The equation of a line that has a slope of m and passes through the midpoints M(3,-2)  is

y-y_{1} =m(x-x_{1} )

y-(-2) =\frac{-1}{3} (x-3 )

(y+2) =\frac{-1}{3} (x-3 )

if we want slope intercept form

(y+2) =\frac{-1}{3} x+1

y= \frac{-1}{3} x-1

If we want standard form

\frac{1}{3} x+y = -1

x+3y =-3

Hence, Equation of a line is x+3y =-3.

To learn more about perpendicular bisector of the line segment from the given link:

brainly.com/question/4428422

#SPJ4

   

7 0
1 year ago
Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min
alina1380 [7]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

We have been given two points on a line (-6,-5) and (-4,-4). We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation y=mx+b, where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

m=\frac{y_2-y_1}{x_2-x_1}

Let point (-6,-5)=(x_1,y_1) and point (-4,-4)=(x_2,y_2).

m=\frac{-4-(-5)}{-4-(-6)}

m=\frac{-4+5}{-4+6}

m=\frac{1}{2}

Now, we will substitute m=\frac{1}{2} and coordinates of point (-6,-5) in slope-intercept form of equation as:

-5=\frac{1}{2}*(-6)+b

-5=-3+b

-5+3=-3+3+b

-2=b

Upon substituting m=\frac{1}{2} and b=-2 in slope-intercept form of equation, we will get our required equation as:

y=\frac{1}{2}x-2

Therefore, our required equation would be y=\frac{1}{2}x-2.

8 0
2 years ago
 plz help need help fast The figure is the net for a rectangular prism.
Art [367]
Two small rectangle at the end areas are:
3x5=15
15x2=30
Longer middle rectangle is:
Length:5+3+5+3=16
Width:9
16x9=144
30+144=174
4 0
3 years ago
Example of cuboid maths ​
Vesnalui [34]

Answer:

the xbox one x fridge

Step-by-step explanation:

8 0
3 years ago
Which could be the area of the base of the triangular prism?
Likurg_2 [28]

Answer:

c - 12ft

Step-by-step explanation:

7 0
2 years ago
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