Y = 1 + i
<span>(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i </span>
<span>(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i </span>
<span>1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i </span>
<span>1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i </span>
<span>-3 - 4i + k = -i </span>
<span>k = 4i - i + 3 </span>
<span>k = 3i + 3 </span>
<span>k = 3 * (1 + i) </span>
<span>k = 3y</span>
Answer:
18
Step-by-step explanation:
-11 - 7 = -18
|-18| = 18
Answer:
A)
Step-by-step explanation:
check that the formula in A works . . .
the 7th term should be 320
a(320) = 5(2)^7-1
= 5(2)^6
= 5(64)
= 320
Answer:
Step-by-step explanation:
Take a look at the attachment...
Hope this helps! :)
