you have to apply this formula (a+b)(c-d)=ac-ad+bc-bd
-6a^3*b*5a^2+6a^3b*2ab+6a^3b*b+2ab^2*5a^2-2ab^2*2ab-2ab^2*b=
-30a^5*b+12a^4b^2+6a^3b^2+10a^3b^2-4a^2b^3-2ab^3
Step-by-step explanation:
Let x be the length of segment AB.
Then the length of segment BC is (2x - 4).
The length of segment AC is x.
We know that x + (2x - 4) + x = 52.
Therefore 4x - 4 = 52, 4x = 56, x = 14.
Hence the length of segment AB is 14.
I believe it's one of the four in photo.
The sector (shaded segment + triangle) makes up 1/3 of the circle (which is evident from the fact that the labeled arc measures 120° and a full circle measures 360°). The circle has radius 96 cm, so its total area is π (96 cm)² = 9216π cm². The area of the sector is then 1/3 • 9216π cm² = 3072π cm².
The triangle is isosceles since two of its legs coincide with the radius of the circle, and the angle between these sides measures 120°, same as the arc it subtends. If b is the length of the third side in the triangle, then by the law of cosines
b² = 2 • (96 cm)² - 2 (96 cm)² cos(120°) ⇒ b = 96√3 cm
Call b the base of this triangle.
The vertex angle is 120°, so the other two angles have measure θ such that
120° + 2θ = 180°
since the interior angles of any triangle sum to 180°. Solve for θ :
2θ = 60°
θ = 30°
Draw an altitude for the triangle that connects the vertex to the base. This cuts the triangle into two smaller right triangles. Let h be the height of all these triangles. Using some trig, we find
tan(30°) = h / (b/2) ⇒ h = 48 cm
Then the area of the triangle is
1/2 bh = 1/2 • (96√3 cm) • (48 cm) = 2304√3 cm²
and the area of the shaded segment is the difference between the area of the sector and the area of the triangle:
3072π cm² - 2304√3 cm² ≈ 5660.3 cm²
