Using the hypergeometric distribution, it is found that there is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.
<h3>What is the hypergeometric distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
For this problem, the parameters are given as follows:
N =A + B = 54, k = 4, n = 4.
The probability of getting exactly two winning numbers with one ticket is P(X = 2), hence:


There is a 0.0232 = 2.32% probability of getting exactly two winning numbers with one ticket.
More can be learned about the hypergeometric distribution at brainly.com/question/24826394
#SPJ1
So to my calculations of copping the other guy it’s -1/-3
Answer:
(-6,-3) would be the answer
Answer:
c. 18 units
Step-by-step explanation:
Points F and K are 3 units apart. (Both are on the horizontal line at y=2, so the segment length is the difference of x-coordinates: 4 -1 = 3.)
Points F and K are adjacent vertices of the hexagon, so the perimeter will be 6 times the length of KF: 6·(3 unit) = 18 units.
Answer
C
Explination
Uh I’m smart