Answer:
Algorithm
Explanation:
An algorithm can assist in solving organizational problems by setting standards that will aid in decision making. They are effective because they use statistical data and past information stored so that through artificial intelligence executives get data that surpasses human limitations. But it should be reviewed by IT professionals to avoid failures.
Jarell is grocery shopping for his bbq cookout this weekend. he is grilling 1313lb. burgers and expects about 20 people. 6.667 lbs. of ground beef should be purchased.
Jarrell should purchase 7 lbs of ground beef.
Number of attendees = 20
Fraction of burger per person = 1/3 lbs
Total fraction of burger required to feed 20 persons :
Number of attendees × fraction per person
20 × 1/3 = 6.667.
Grilling is a cooking method that applies dry heat to the surface of food, usually from the top, bottom, or sides. Grills typically use large amounts of direct radiant heat and are typically used to quickly cook meat and vegetables.
Almost all types of grilling on gas and/or charcoal grills can be divided into three cooking methods: direct, indirect, or combination. As the name suggests, method differences are determined as follows.
Learn more about grilling at
brainly.com/question/13973768
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Answer:
A
Explanation:
Saving early will allow you to gain more money because your interest will build over time.
Answer:
Following are the solution to this question:
Explanation:
Assume that
will be a 12-month for the spot rate:


Assume that
will be a 18-month for the spot rate:



Assume that
will be a 18-month for the spot rate:

to solve this we get 