Answer:
FOR REGULAR PYRAMID with those dimension.
L.A = 96
FOR HEXAGONAL PYRAMID with those dimension
L.A = 171.71
Step-by-step explanation:
Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.
Hence I solved for both:
FOR REGULAR PYRAMID
Lateral Area (L.A) = 1/2* p * l
Where p = Perimeter of base
P = 4s
P = 4 * 6
P = 24cm
l = slanted height
l = 8cm
L.A = 1/2 * 24 * 8
L.A = 1/2 ( 192)
L.A = 96cm ^ 2
FOR AN HEXAGONAL PYRAMID
Lateral Area = 3a √ h^2 + (3a^2) / 4
Where:
a = Base Edge = 6
h = Height = 8
L.A = 3*6 √ 8^2 + ( 3*6^2) / 4
L.A = 18 √ 64 + ( 3 * 36) / 4
L.A = 18 √ 64 + 108/4
L.A = 18 √ 64+27
L.A = 18 √ 91
L.A = 18 * 9.539
L.A = 171.71
Answer:
19% done
81% left
Step-by-step explanation:
95/500=19
100-19=81
I believe the answer would be A. 96in2
Hey. This equation has infinite many solutions.
3x - 3x - 2 = - 2
3x - 3x = 0
3x = 3x
This equals to each other meaning infinite solutions
Answer:
Step-by-step explanation:
area of sector=πr²/4=π ×6²/4=9 π ft²
area of one triangle= 1/2×6×6=18 ft²
area of three triangles=3×18=54 ft²
area of sector +area of three triangles=54+9 π ft²
area of circle=π×6²=36 π ft²
area of shaded region=36 π-9π-54=27 π-54=27(π-2) ft²