Answer:


Step-by-step explanation:
We know that the mean and the standard error of the sampling distribution of the sample proportions will be :-


, where p=population proportion and n= sample size.
Given : The proportion of students at a college who have GPA higher than 3.5 is 19%.
i.e. p= 19%=0.19
The for sample size n= 25
The mean and the standard error of the sampling distribution of the sample proportions will be :-


Hence , the mean and the standard error of the sampling distribution of the sample proportions :


Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get


Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
0.86/5-0.3*0.5= 2 answers
1. can be 11/500
2. it can be 0.022 but im positive it has to be 11/500
Answer:
Step-by-step explanation:
Just substitute in 7 for the n.
30-4(7)
30-28
2
The 7th term in the sequence is 2.
(please give brainliest?)