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2 years ago

Please help,find all the missing side and angle measures

Mathematics

1 answer:

Alex2 years ago

7 0

We cannot find the side measures unless there is another side given.
K=90
L= 90-24 = 66
answers: K=90
L=66

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Marianne has 5/8 package of peas. She cooks 2/3 of those peas for 5 people. If each person is served an equal amount, what fract

creativ13 [48]

5/8 and 2/3 so...
8 times 3 is 24 so now put your fraction over twenty four
15/24=5/8
15/24 so fifteen out of twenty fourths of the package is what she has. She takes ten out of the fifteenths because fifteen divided by three is five then multiply by two is ten. Then divide by five and you get two.
15/24. 10-> 15/24 cause... 15 divided by 3 ( from the two thirds she cooked) is 5 then * by 2... 5*2=10

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2 years ago

Label x-intercepts, vertex and axis of symmetry for f(x) = (x+3)(x-5)

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X intercepts are -3 and 5

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2 years ago

Find a nonzero vector orthogonal to the plane through the points: ????=(0,0,1), ????=(−2,3,4), ????=(−2,2,0).

ser-zykov [4K]

Answer:

The nonzero vector orthogonal to the plane is <-9,-8,2>.

Step-by-step explanation:

Consider the given points are P=(0,0,1), Q=(−2,3,4), R=(−2,2,0).

$\overrightarrow {PQ}==$

$\overrightarrow {PR}==$

The nonzero vector orthogonal to the plane through the points P,Q, and R is

$\overrightarrow n=\overrightarrow {PQ}\times \overrightarrow {PR}$

$\overrightarrow n=\det \begin{pmatrix}i&j&k\\ \:\:\:\:\:-2&3&3\\ \:\:\:\:\:-2&2&-1\end{pmatrix}$

Expand along row 1.

$\overrightarrow n=i\det \begin{pmatrix}3&3\\ 2&-1\end{pmatrix}-j\det \begin{pmatrix}-2&3\\ -2&-1\end{pmatrix}+k\det \begin{pmatrix}-2&3\\ -2&2\end{pmatrix}$

$\overrightarrow n=i(-9)-j(8)+k(2)$

$\overrightarrow n=-9i-8j+2k$

$\overrightarrow n=$

Therefore, the nonzero vector orthogonal to the plane is <-9,-8,2>.

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3 years ago

the tax on a property with an assessed value of $64,000 is $650. Using a proportion, find the tax on a property with an assessed

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The answer is $1200.

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2 years ago

What is the horizontal distance between the two points (-7,-4) and (12,-4)? Remember that distance is always positive! Hint: The

RSB [31]

<h3>Answer: 19</h3>

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Explanation:

Draw out a number line. Plot -7 and 12 on the number line. Draw in the tickmarks between them. You should find the distance from -7 to 12 is 19 units since you need to go 19 spaces from either -7 to 12, or vice versa.

You can use subtraction to get

-7-12 = -19

12-(-7) = 12+7 = 19

The final result is made positive since negative distance does not make sense.

So you'd have |-7-12| = |-19| = 19 or |12-(-7)| = |19| = 19.

All of this only works because the two y coordinates are the same, which makes a horizontal line through the two given points.

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2 years ago