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marusya05 [52]
3 years ago
6

Which box depicts the tissue level of organization? A) P B) Q C) R D) S

Physics
1 answer:
sveta [45]3 years ago
8 0
The right answer is Q).

Explanation:
P) Depicts organ level of organization.
R) Depicts cellular level of organization.
S) Depicts Organ System level of organization.
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Why metal wire coated with plastic or rubber is used in electric circuits
kolezko [41]
Because plastic and rubber are known as insulators which keep metal wires protected
7 0
4 years ago
Need Help !
Bad White [126]

Answer: 5.96m/s

Explanation:

Given the following :

Mass of car (m) = 1500kg

Velocity (V) = 5.25m/s

Forward force of engine = 1250N

Diatance moved = 4.8m

Final Velocity =?

Final kinetic energy = Initial kinetic energy + work done by engine

Initial kinetic energy = 0.5 × mass × velocity^2

Initial kinetic energy = 0.5 × 1500 × 5.25^2

Initial kinetic energy = 20671.875 J

Work done by engine = Force × distance

Work done by engine = 1250 × 4.8 = 6000J

Final kinetic energy = (20671.875 + 6000) J

= 26671.875 J

From kinetic energy = 0.5mv^2

26671.875 = 1/2 × 1500 × v^2

53343.75 = 1500v^2

v^2 = 35.5625

v = sqrt(35.5625)

v = 5.96m/s

3 0
3 years ago
Which event is an example of melting?
qaws [65]

Answer:

welding metal

Explanation:

5 0
3 years ago
You and your lab partner, Mel, are engrossed in a chemistry activity using beans to compute the average atomic mass of an elemen
Vikentia [17]

Answer:

C:

Explanation:

either C or A but A seems unlikely after multiple attempts. Although the question doesn't make it clear whether the balance is electric either way it could be wrong in someway and seems to be the most likely.

5 0
3 years ago
Read 2 more answers
34. A train, starting from rest, accelerates along the platform at a uniform rate of 0.6 m/s2. A passenger standing on the platf
ira [324]

Answer:

4.08 s

Explanation:

Let the passenger took "t" time to catch the train

so in this case the total distance moved by the train + 5 m = total distance moved by the passenger

so we will have

distance moved by train is given as

d_1 = \frac{1}{2}(0.6) t^2

also the distance moved by passenger

d_2 = \frac{1}{2}(1.2) t^2

so we will have

d_1 + 5 = d_2

0.3 t^2 + 5 = 0.6 t^2

0.3 t^2 = 5

t = 4.08 s

3 0
4 years ago
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