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amm1812
3 years ago
14

A dipole of moment 0.50 e · nm is placed in a uniform electric field with a magnitude of 1.6 105 N/C. What is the magnitude of t

he torque on the dipole for each of the following situations?
(a) the dipole is aligned with the electric field
(b) the dipole is transverse to (perpendicular to) the electric field
(c) the dipole makes an angle of 26° with the direction of the electric field
(d) Defining the potential energy to be zero when the dipole is transverse to the electric field, find the potential energy of the dipole in the electric field for the orientations specified in Parts (a) and (c).
Physics
1 answer:
gtnhenbr [62]3 years ago
5 0
Too much to read bro bro
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We know there’s a change in momentum due to a force applied over a time interval. Ft= m[v(final)-v(initial)]. Now simply plug in know values: (45)(0.02)=.005[v(final)-0]. Remember converting grams to kilograms. Solve for v final

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When you drop a strong magnet through the center of a copper pipe, what happens to the copper piper and the magnet?
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Explanation:

7 0
3 years ago
A 66.0 kg diver is 2.30 m above the water, falling at speed of 2.20 m/s. Calculate her kinetic energy as she hits the water. (Ne
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The kinetic energy of the diver as she hits the water is 159.72J. Details about kinetic energy can be found below.

<h3>How to calculate kinetic energy?</h3>

The kinetic energy of a body can be calculated using the following formula:

K.E = ½ × m × v²

Where;

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  • m = mass
  • v = velocity

According to this question, a 66.0 kg diver is 2.30 m above the water and falls at speed of 2.20 m/s.

Kinetic energy = ½ × 66 × 2.2²

K.E = 159.72J

Therefore, the kinetic energy of the diver as she hits the water is 159.72J.

Learn more about kinetic energy at: brainly.com/question/12669551

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6 0
2 years ago
In old cartoons, sometimes they would drop a piano on a toon’s head. If a piano weighs 215.5 kg and us falling at a rate of 9.8
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Answer:

<h3>F=2,111.9</h3>

F= two thousand one hundred eleven point nine

Explanation:

Force equals <em><u>Mass(kg)</u></em> times acceleration (M/s^2)

F=<em><u>m</u></em>a

F= <u><em>215.5</em></u> x 9.8

5 0
4 years ago
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