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amm1812
3 years ago
14

A dipole of moment 0.50 e · nm is placed in a uniform electric field with a magnitude of 1.6 105 N/C. What is the magnitude of t

he torque on the dipole for each of the following situations?
(a) the dipole is aligned with the electric field
(b) the dipole is transverse to (perpendicular to) the electric field
(c) the dipole makes an angle of 26° with the direction of the electric field
(d) Defining the potential energy to be zero when the dipole is transverse to the electric field, find the potential energy of the dipole in the electric field for the orientations specified in Parts (a) and (c).
Physics
1 answer:
gtnhenbr [62]3 years ago
5 0
Too much to read bro bro
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A child with a weight of 110 N swings on a playground swing attached to 2.00 m long chains. What is the gravitational potential
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Answer

given,

Weight of the child = 110 N

length of the swing,L = 2 m

now, calculating the potential energy when the string is horizontal

  Potential energy = m g h

 now, h = L (1 - cos θ)   where θ is the angle made by the string with the vertical.

     PE = m g L (1 - cos θ)

   when rope is horizontal θ = 90°

     PE = 110 x 2 (1 - cos 90°)

    PE = 220 J

now, calculating potential energy when string made 25° with horizontal

PE = m g L (1 - cos θ)

   when rope is horizontal θ = 25°

     PE = 110 x 2 (1 - cos 25°)

     PE = 20.61 J

5 0
4 years ago
The energy that a substance contains is
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The energy that substance contain is. B.heat
8 0
3 years ago
A car accelerates from rest at 3m/s2 along a straight road how far has the car traveled after 4s?
murzikaleks [220]

Answer:

24 m

Explanation:

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7 0
3 years ago
A cliff diver from the top of a 100 (m) cliff. He begins his dive by jumping up with a velocity of 5 (m/s) a. How
Nutka1998 [239]

Answer:

A.) 4.81 seconds

B.) 44.6 m/s

Explanation:

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Let us first calculate the maximum height reached by using third equation of motion

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At maximum height, V = 0

0 = 5^5 - 2 × 9.8H

19.6H = 25

H = 25 /19.6

H = 1.28 m

The time taken for the diver to reach the water from the maximum height can be calculated by using second equation of motion.

Where height h = 1.28 + 100 = 101.28 m

h = Ut + 1/2gt^2

As the diver drop from maximum height, U = 0

101.28 = 1/2 × 9.8 × t^2

4.9t^2 = 101.28

t^2 = 101.28/4.9

t^2 = 20.669

t = sqrt ( 20.669)

t = 4.55s

As the diver jumped up, the time taken to reach the maximum height will be

Time = 1.28 / 5 = 0.256

The time taken for him to hit the water below will be 0.256 + 4.55 = 4.81 seconds

B.) Velocity right before he hits the water will be

V^2 = U^2 + 2gH

But U = 0

V^2 = 2 × 9.8 × 101.28

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V = 44.6 m/s

6 0
4 years ago
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Electromagnetic waves all have the same velocity in the same medium.  However, since frequencies vary widely, so do wavelengths.

4 0
3 years ago
Read 2 more answers
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